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Engaging Mathematics through Contextualized Learning in SHSM Programs

This activity focuses on contextualized learning within the Specialist High Skills Major (SHSM) program, helping students explore mathematics through real-world applications. Students will create multimedia presentations employing Photoshop and Premiere Elements, illustrating concepts such as quadratic functions. By engaging in hands-on activities, they enhance their understanding and appreciation of mathematical principles. The assignment culminates in a PowerPoint presentation that showcases their animations and demonstrates the mathematical reasoning behind them, thus reinforcing the relevance of math in various fields.

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Engaging Mathematics through Contextualized Learning in SHSM Programs

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  1. Contextualized Learning ActivityInformation and Communications Technology (SHSM)TGJ3MIMathematics Functions and Applications MCF3MI SHSM Specialist High Skills Major

  2. Contextualized Learning Activity An SHSM allows students to experience a range of customized learning opportunities in an area that interests them, and helps to engage them in their school program. • http://www.edu.gov.on.ca/eng/studentsuccess/pathways/shsm/shsm_fact_sheet.pdf

  3. Exemplar MCF-3M Mathematics Functions Multi-Media Assignment Photoshop animation and edited by Premiere Elements for audio, transitions and titles.

  4. Exemplar MCF-3M Mathematics Functions Multi-Media Assignment Photoshop animation gif file inserted into powerpoint

  5. Exemplar MCF-3M Mathematics Functions Multi-Media Assignment Here’s a picture of the animation you just saw. The numbers are estimated. PowerPoint media can be used to show how the quadratic function is determined, as follows:

  6. ←x - axis A B ↑ 0 – metre line In this example,, from the animation, we’ll assume person “A” is on the “0” metre line and that the x-axis passes through the players’ hands (this will simplify the calculations).

  7. A If person A is on the “0” metre line; the zeroes for this parabola are therefore… (0,0)and (6,0).

  8. And the vertex is… (3,4).

  9. Substituting these values (f(x)= 4; x = 3; s = 0; t = 6) into the zeroes or factoredformf(x)=a(x – s)(x – t) gives…

  10. f(x)=a(x – s)(x – t) gives: Now we have all the values we need for an equation of this function 4 = a(3 – 6)(3 – 0) 4 = a(-9) a = This would mean that the football’s path represents a parabola that opens down, with a maximumvertex of (3,6) and function equation (in zeroes or factored form) of…

  11. (This is zeroes or factoredform). Or, in vertexform:

  12. (This is zeroes or factoredform). Or, in vertexform: Finally, in standardform this is:

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