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## Area of Triangle

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**A**C B a 1 = A ah 2 Area of Triangle c b h**A**c = h c sin B 1 = Area ah 2 C B a 1 = ac sin B 2 • If only a, c and ABC are given …. h**A**b c a B N C Other case h**A**1 = Area ab sin C c b 2 1 = bc sin A 2 B C a 1 = ca sin B 2 In conclusion**A**9 cm 8 cm 120° C B 1 2 = x x x Area ( 8 9 sin120 )cm 2 2 = 31.2cm Example 1**Y**= Area 32 cm 2 10 cm X Z 8 cm Example 2 :**=**Area 110 cm 2 P = Area 110cm 2 18 cm x cm = 17 . 3 R Q Example 3 :**A**B 4 cm 130° 1 = x x x ° Area of BCD ( 4 5 sin130 )cm 2 5 cm C D 2 = 7.660 4cm 2 = x 2 area of BCD = x (2 7.660 4) cm 2 = 15.3cm 2 Example 4 :