1 / 12

Universal Elimination

Understand the concept of Universal Elimination in predicate logic with examples and the official definition. Learn how to apply this inference rule correctly.

hewing
Download Presentation

Universal Elimination

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Universal Elimination  Kareem Khalifa Department of Philosophy Middlebury College

  2. Overview • What is Universal Elimination? • A commonsense example • The official definition • Examples

  3. What is Universal Elimination? • From a generalization, infer an instance of that generalization. • Ex. Everybody is happy. So John is happy. • Ex. All birds are mortal. Tweety is a bird. So Tweety is mortal. • Perhaps the most basic of our four basic inference rules in predicate logic.

  4. The examples examined • Ex. Everybody is happy. So John is happy.xHx ├ Hj • xHx A • Hj 1 E • Ex. All birds are mortal. Tweety is a bird. So Tweety is mortal. x(Bx→Mx), Bt ├ Mt • x(Bx→Mx) A • Bt A • Bt→Mt 1 E • Mt 2,3 →E

  5. The official definition • Universal Elimination (E): Let Φ be any universally quantified formula and Φ/ be the result of replacing all occurrences of the variable  in Φ by some name . Then from Φ, infer Φ/. • x(Bx→Mx) A • Bt A • Bt→Mt 1 E • Mt 2,3 →E

  6. Some finer points… • When you have multiple quantifiers, you apply E from left to right (outside-in), e.g. • Everyone loves everyone. So Al loves Bob. • xyLxy A • yLay 1 E • Lab 2 E • Note that this is the exact opposite direction as I.

  7. Another finer point… • Be strategic in which name you instantiate when using E. • Example: Either Al or Ben is the winner. All winners must have passed the qualifying round. Ben did not. So Al is the winner. • Wa v Wb A • x(WxQx) A • ~Qb A • WaQa 2 E • ~Wb 3,4MT • Wa 1,5 DS Imprudent. WbQb

  8. Samples: Nolt 8.3.1.1 ├ xFx → Fa 1. | xFx H for →I 2. | Fa 1 E 3. xFx→Fa 1-2 →I

  9. 8.3.1.4 x(Fx→Gx), Ga→Ha ├ Fa →Ha 1. x(Fx→Gx) A 2. Ga→Ha A 3. Fa→Ga 1 E 4. Fa→Ha 2,3 HS

  10. 8.3.1.7 x(Fx→Gx), x~Gx ├ x~Fx 1. x(Fx→Gx) A 2. x~Gx A 3. |~Ga H for E 4. |Fa→Ga 1 E 5. |~Fa 3,4 MT 6. |x~Fx 5 I 7. x~Fx 2,3-6 E

  11. 8.3.1.8 x(Fx→Gx), ~xGx ├ ~xFx 1. x(Fx→Gx) A 2. ~xGx A 3. |xFx H for ~I 4. | |Fa H for E 5. | |Fa→Ga 1 E 6. | |Ga 4,5→E 7. | |xGx 6 I 8. |xGx 3,4-7 E 9. |xGx & ~xGx 2,9 &I 10. ~xFx 3-9 ~I 7. | | xGx 6I 8. | |P&~P 2,7 EFQ 9. | P&~P 3,4-8 E 10.~xFx 3-9 ~I (Alternative Proof)

  12. 8.3.1.10 • xFx v xGx, ~Ga ├ xFx • 1. xFx v xGx A • 2. ~Ga A • 3. |xGx H for ~I • 4. |Ga 3 E • 5. |Ga & ~Ga 2,5 &I • 6. ~xGx 3-5 ~I • 7. xFx 1,6 DS

More Related