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Solving Money Problems with Different Bill and Coin Combinations

Understand, plan, and solve how Casey and Jerald paid for movie tickets using different bill and coin combinations for $6.45. Learn to find the least number of bills and represent the amount in multiple ways. Check your solutions for accuracy.

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Solving Money Problems with Different Bill and Coin Combinations

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  1. 3-2 Lesson 4-2 Example 4 Solve. MONEY Casey and Jerald each purchased a ticket to the movies at $6.45 each. They used a different combination of bills and coins to pay. Represent $6.45 in two ways. Understand Read the problem. Write what you know. Each person paid a total of $6.45.

  2. 3-2 Lesson 4-2 Example 4 Plan Pick a strategy. One strategy is to use logical reasoning. First represent $6.45 using the fewest coins. Then find a combination using different coins and bills.

  3. 3-2 Lesson 4-2 Example 4 Solve The least number of bills that can make $6.45 is one5-dollar bill and one1-dollar bill. What amount is left? 45¢ Which coin represents the greatest amount? a quarter 25¢ +10¢= 35¢ 35¢ +10¢= 45¢ So, one combination for $6.45 isone 5-dollar bill, one 1-dollar bill, one quarter, two dimes.

  4. +10¢ +10¢ +10¢ +5¢ 3-2 Lesson 4-2 Example 4 Solve Now represent $6.45 using a different combination of bills and coins. $6=six 1-dollar bills 45¢ = 10¢ 20¢ 30¢ 40¢ 45¢ 45¢ = 10¢ 20¢ 30¢ 40¢ 45¢ = 10¢ 20¢ 30¢ 45¢ = 10¢ 20¢ 45¢ = 45¢ = 10¢ A second combination of bills and coins issix 1-dollar bills, four dimes, one nickel.

  5. 3-2 Lesson 4-2 Example 4 Check Add each amount. The total of each amount should be $6.45.

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