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 四位以內的加減混合題

3A 冊.  四位以內的加減混合題.  加減混合應用題. 1248 + 2051  148. + 1 2 4 8 + 2 0 5 1. =  148. =.  1 4 8. 從左至右逐步計算。. 這算式應怎樣計算？. 1248 + 2051  148 = ？. 3299. 3 2 9 9. 3151. 3 1 5 1. 減時留意退位，加時留意進位。. 3 0 0 2  1 4 5 9. 3002  1459 + 2677. = + 2677.

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 四位以內的加減混合題

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  1. 3A冊 四位以內的加減混合題 加減混合應用題

  2. 1248 + 2051  148 + 1 2 4 8 + 2 0 5 1 =  148 =  1 4 8 從左至右逐步計算。 這算式應怎樣計算？ 1248 + 2051  148 = ？ 3299 3 2 9 9 3151 3 1 5 1

  3. 減時留意退位，加時留意進位。 3 0 0 2  1 4 5 9 3002 1459 + 2677 = + 2677 = + 2 6 7 7 3002  1459 + 2677 = ？ 1543 4220 1 5 4 3 4 2 2 0

  4. 遊戲天地獎品換領 1250 張 3785 張 4235 張 4565 張 2540 張 8460 張 用指定數量的 可換取以下的獎品。

  5. 換領 要 1250 張， 要 4235 張。子恩只有4926 張 ，她想換 領 和 ，還欠 多少張﹖ 還欠 ： 1250 + 4235  4926 =  4926 1 2 5 0 + 4 2 3 5  4 9 2 6 = (張) 5 4 8 5 5485 先計算換領兩件玩具的總票數 559 5 5 9 再計算子恩還欠的票數

  6. 子明原有 5000 張，換領 用去 4565 張，他再玩遊戲後得 980 張。他現 有 多少張﹖ 他現有 ： 5000  4565 + 980 = + 980 5 0 0 0  4 5 6 5 + 9 8 0 = (張) 4 3 5 435 先計算子明換領玩具後餘下的票數 1415 1 4 1 5 再加上子明玩遊戲後所得的票數

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