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ENE 428 Microwave Engineering. Lecture 2 Uniform plane waves. Propagation in lossless-charge free media. Attenuation constant  = 0, conductivity  = 0 Propagation constant Propagation velocity for free space u p = 310 8 m/s (speed of light)

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ENE 428Microwave Engineering

Lecture 2 Uniform plane waves

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propagation in lossless charge free media
Propagation in lossless-charge free media
  • Attenuation constant  = 0, conductivity  = 0
  • Propagation constant
  • Propagation velocity
    • for free space up = 3108 m/s (speed of light)
    • for non-magnetic lossless dielectric (r = 1),

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propagation in lossless charge free media1
Propagation in lossless-charge free media
  • intrinsic impedance
  • wavelength

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Ex1 A 9.375 GHz uniform plane wave is propagating in polyethelene (r = 2.26). If the amplitude of the electric field intensity is 500 V/m and the material is assumed to be lossless, find

a) phase constant

b) wavelength in the polyethelene

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c) propagation velocity

d) Intrinsic impedance

e) Amplitude of the magnetic field intensity

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propagation in dielectrics
Propagation in dielectrics
  • Cause
    • finite conductivity
    • polarization loss ( = ’-j” )
  • Assume homogeneous and isotropic medium

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propagation in dielectrics2
Propagation in dielectrics

We can derive

and

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loss tangent
Loss tangent
  • A standard measure of lossiness, used to classify a material as a good dielectric or a good conductor

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low loss material or a good dielectric tan 1
Low loss material or a good dielectric (tan « 1)
  • If or < 0.1 , consider the material ‘low loss’, then

and

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high loss material or a good conductor tan 1
High loss material or a good conductor (tan » 1)
  • In this case or > 10, we can approximate

therefore

and

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high loss material or a good conductor tan 11
High loss material or a good conductor (tan » 1)
  • depth of penetration or skin depth,  is a distance where the field decreases to e-1or 0.368 times of the initial field
  • propagation velocity
  • wavelength

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ex2 given a nonmagnetic material having r 3 2 and 1 5 10 4 s m at f 3 mhz find
Ex2 Given a nonmagnetic material having r= 3.2 and  = 1.510-4 S/m, at f = 3 MHz, find

a) loss tangent 

b) attenuation constant 

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c) phase constant 

d)intrinsic impedance

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Ex3 Calculate the followings for the wave with the frequency f = 60 Hz propagating in a copper with the conductivity,  = 5.8107 S/m:

a) wavelength

b) propagation velocity

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attenuation constant
Attenuation constant 
  • Attenuation constant determines the penetration of the wave into a medium
  • Attenuation constant are different for different applications
  • The penetration depth or skin depth, 

is the distance z that causes to reduce to

z = 1

 z = 1/  = 

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good conductor
Good conductor
  • At high operation frequency, skin depth decreases
  • A magnetic material is not suitable for signal carrier
  • A high conductivity material has low skin depth

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currents in conductor
Currents in conductor
  • To understand a concept of sheet resistance

from

Rsheet()

sheet resistance

At high frequency, it will be adapted to skin effect resistance

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currents in conductor1
Currents in conductor

Therefore the current that flows through the slab at t   is

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currents in conductor2
Currents in conductor

From

Jxor current density decreases as the slab gets thicker

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currents in conductor3
Currents in conductor

For distance L in x-direction

Ris called skin resistance

Rskinis called skin-effect resistance

For finite thickness,

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currents in conductor4
Currents in conductor

Current is confined within a skin depth of the coaxial cable

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Ex A steel pipe is constructed of a material for which r = 180 and  = 4106 S/m. The two radii are 5 and 7 mm, and the length is 75 m. If the total current I(t) carried by the pipe is 8cost A, where  = 1200 rad/s, find:
  • The skin depth
  • The skin resistance

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the poynting theorem and power transmission
The Poynting theorem and power transmission

Poynting theorem

Total power leaving

the surface

Joule’s law

for instantaneous

power dissipated

per volume (dissi-

pated by heat)

Rate of change of energy stored

In the fields

Instantaneous poynting vector

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example of poynting theorem in dc case
Example of Poynting theorem in DC case

Rate of change of energy stored

In the fields = 0

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example of poynting theorem in dc case1
Example of Poynting theorem in DC case

From

By using Ohm’s law,

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example of poynting theorem in dc case2
Example of Poynting theorem in DC case

Verify with

From Ampère’s circuital law,

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uniform plane wave upw power transmission
Uniform plane wave (UPW) power transmission
  • Time-averaged power density

W/m2

amount of power

for lossless case,

W

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uniform plane wave upw power transmission1
Uniform plane wave (UPW) power transmission

for lossy medium, we can write

intrinsic impedance for lossy medium

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