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Current Electricity. e-. P. n. nucleus. Electrons. Electrons Flow. Conventional Current. Flow of Electrons (Path). -. +. e -. e -. e -. e -. e -. e -. e -. e -. e -. e -. Conventional Current. Flows from + to -. e. e. e. e. e. Current. Flow of Electrons.
E N D
e- P n nucleus Electrons
Electrons Flow Conventional Current Flow of Electrons (Path) - + e- e- e- e- e- e- e- e- e- e-
Conventional Current Flows from + to -
e e e e e Current Flow of Electrons Metals - Free Electrons
e e e e e e e e e e e e e e e e Current Flow of charge (q)! q - Coulomb(C) 6.24 X 1018 electrons
e e e e e e e e e e e e e e e e Current Amount of charge passing a point in a second.
Charge Time Current = Current Symbol - I Unit – Ampere (Amps) Amperes - A
Charge Time Q t Current = I = Current
Coulomb Second Ampere = C S 1 A = 1 Current
e e e e e e e e e e e e e e e e Force Voltage Potential Difference Electromotive Force (EMF)
Voltage Symbol - V Unit – Volt Volt - V
Resistance Opposition to Current Flow High Resistance Insulator
Resistance Opposition to Current Flow Low Resistance Conductor
Resistance Opposition to Current Flow High and Low Resistance SemiConductor
Resistance Symbol - R Unit – Ohm Ohm - Ω
Load Source Path Putting it all Together
I _ V R + Schematic Diagram Path Source Load
I _ V R + Mathematical Equation V = IR
Ohm’s Law Ohm’s Law The mathematical relationship between Current, Voltage and Resistance.
V I R Ohm’s Law Wheel Find: V V = IR
V VR I = I R Ohm’s Law Wheel Find: I
V V I R = I R Ohm’s Law Wheel Find: V
I _ R=500Ω V=10v + Example
V I R VR 10V500Ω I = = Example Given: V=10v R=500Ω Find: I = ? Equation: I = 0.02A = 20mA
Homework:22-1 Prob: 1,3,4,8,9, 11,14,17,20 Page 526, 527 Due: 3/20/07
Power Power measures the rate at which energy is transferred. In the case of electric current, charge is being transferred
Power Symbol - P Unit – Watt Watt - W
Power Power = Current X Voltage P = IV
P I V Power Wheel Find: P P = IV
P PV I = I V Power Wheel Find: I
P PI V = I V Power Wheel Find: V
V P V2R I I V R P = Power Equations P = IV P = I2R
Conductor Switch Fuse Capacitor Resistor Variable Resistor Schematic Symbols
Battery dc generator Ammeter A Connection No Connection Ground Schematic Symbols Voltmeter V
R1 _ V R2 V + A Schematic Diagrams
Meter Placement Voltmeters are placed parallel to the component being measured. Ammeters are placed in series with the component being measured.
Using Electric Energy Energy used in an Electric Circuit. P = E/t E = Pt
Using Electric Energy E = IVt E = I2Rt E = (V2/R)t
_ R=500Ω V=100v + Example How much energy is used in 1minute???
V2t R E = (100V)2(60s) 500Ω E = Example Given: V=100v R=500Ω t=1min=60s Find: E = ? Equation: = 1200J
Homework:22-2 Practice Problems: 11-17 Page 517, 522 Due: 5/29/03
Transmission ofElectric Energy Minimize Power Losses P = I2R Decrease Current Increase Voltage - 500,000V
The Kilowatt-Hour The Electric Company charges you for the amount of energy in Kilowatt-Hours. A Kilowatt-Hour is equal to 1000W delivered continuously for 1 hour(3600s).
The Kilowatt-Hour 1kWh = (1000W)(1 hour) 1kWh = (1000J/s)(3600s) 1kWh = 3.6 X106 J E = Pt
Kilowatt-Hour Example A TV set draws 2.0A at 120V when operating. If the set is on 5 hours a day for 30 days, how much does it cost to run the set? 1 kilowatt-hour cost $0.12.
Kilowatt-Hour Example Given: V=120v I=2A t=(5h/day)(30days) t=150h Find: E = ? Cost
Kilowatt-Hour Example Equation: E = Pt E = Ivt E = (2A)(120V)(150h) E = 35000Wh = 35kWh Cost = (35kWh)($0.12) Cost = $4.20