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##### Math Jeopardy Grade 9

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**400 Points**Dylan and Mike C. went to the movies with Emma and Nicole. If the tickets (with tax) cost twenty seven dollars, how much did each person pay to see the movie? (Assume each paid the same price of admission)**Answer**$27 ÷ 4 people = $6.75 Each person paid $6.75 to go to the movies. If the guys were gentlemen, they would have paid for the girls and thus would pay double, or $13.50.**400 Points**Dylan R, Joel, and Jessie formed a band for the NRCS “Battle of the Bands” competition. They were so good, they won the first place prize of $200! However, they had to pay Town’s End Strings and Things $50 for the rental of their amp. How much money did the boys each net from their contest winnings?**400 Points**Amanda, Nicole, Kaitlyn, Mike F, Craig, and Kaylee each paid for three and one-half slices of pizza each at lunch today. What was the total number of slices of pizza purchased from Margaret’s cafeteria?**Answer**6 people x 3 ½ slices of pizza each = 21 slices of pizza**Answer**(+200) + (-50) = (+150) (+150) ÷ 3 band members = (+50) Each band member took home $50.**400 Points**Colby arrived early to school one day and found that the heating system was not working. The temperature of the building was at -6oC. So he trudged down to the boiler room, yelled mightily, and low and behold the furnace flared to life. Within minutes his classroom was a toasty 19oC. What was the difference in temperature from when he arrived, to when the furnace came to life?**Answer**19oC – (-6oC) = 25oC Colby’s efforts increased the temperature of the classroom by 25 degrees celsius.**600 Points**Kaylee invited her friends over for a pizza party. Two 40cm diameter pizzas arrived from Needs Convenience. They had been pre-cut into 1/12 slices. How many slices of pizza did Kaylee have to share with her friends?**Answer**2 ÷ 1/12 = how many groups of 1/12 slices are found in 2 pizzas? since there are 12 groups of 1/12 in one pizza, there must be 24 groups of 1/12 in two pizzas. Kaylee has 24 slices of pizza to share with her friends.**600 Points**Dexter brought three pounds of rock candy to school one day, to share with his friends. By the end of the day he had given out one and three-quarters of a pound of candy. At the end of the day, what was the remaining weight of candy in Dexter’s school bag?**Answer**Problem: 3 lbs of candy – 1 ¾ lbs of candy Solution: 3 – 1 = 2 lbs 2 – ¾ = 1 ¼ lbs Dexter is taking 1 ¼ pounds of candy home.**600 Points**Dylan ate one-eighth of Jenna’s birthday cake. If Jenna’s other three guests ate one-eighth of the cake each, and Jenna ate another one-fourth of the cake, what was the total amount of cake eaten (as a fraction of the whole cake)?**Answer**1/8 + (1/8 + 1/8 + 1/8) + 1/4 Dylan Other Guests Jenna 1/8 + 3/8 + 2/8 = 6/8 or 3/4 They ate a total of ¾ of Jenna’s birthday cake.**800 Points**Write a short convincing math story problem that involves the following symbolic equation: 24 ÷ 6 = 4 This problem is unlimited in time, setting, and characters. You decide.**Possible Answer**Mr. Butt separated his grade nine math class into six groups for an activity. If he began class with twenty four students, how many students could he put into each group?**800 Points**Write a short convincing math story problem that involves the following symbolic equation: 2 x 24 = 48 This problem is unlimited in time, setting, and characters. You decide.**Possible Answer**Mr. MacNeill decided to “talk” to both classes of grade 8 students regarding their math marks. If both classes were equal in number, and one class had 24 students. What would be the size of this group of students?**800 Points**Write a short convincing math story problem that involves the following symbolic equation: 32 – 3 – 2 = 17 This problem is unlimited in time, setting, and characters. You decide.**Possible Answer**Thirty two hockey players tried out for the South Shore Mustangs team. At the first practice the coaches cut three players from the team. During the second practice they decided to eliminate two more players. Finally they achieved their goal: three lines and two goalies or seventeen players.**200 Points**Emily spent the day sorting her earring collection. She found that she had ten pairs of studs, twelve pairs of hoop earrings, and 5 pairs of funky exotic earrings. When she finished counting, she found that she had exactly ____ earrings.**Answer**10 x 2 studs = 20 studs (Five groups of two) 12 x 2 hoop = 24 hoop (twelve groups of two) 5 x 2 exotic = 10 exotic (ten groups of two) She has 54 earrings in total.**600 Points**In Mr. Butt’s grade nine classes ½ of the twenty-four girls have blonde or red hair. One-half of the remaining students, with brown or black hair, have brown eyes. What number of students in Mr. Butt’s grade nine classes are brown/black haired girls, with brown eyes?**Answer**½ x 24 girls = 12 (blonde/red head) one half of a group of twenty four = twelve The other half (12 girls) must have brown/black hair. ½ x 12 = 6 (brown/black hair & brown eyes) one half of a group of twelve = six There are 6 girls in Mr. Butt’s grade 9 math class with brown/black hair and brown eyes.**200 Points**Mr. Nicholson picked 425 stalks of Rhubarb out of his garden. He brought his produce to school to distribute evenly amongst those persons wishing to acquire some of his bounty. Trent, Jamie, Josh, Mr. Butt, Mrs. Donat, Mrs. Willman, Mr. Mac, Ms. Curran, William, and Jocelyn asked him very nicely. If he agreed to give them each an equal portion of his harvest, how many stalks of Rhubarb did each of these people receive from Mr. Nicholson?**Answer**425 divided into 10 groups would give you 42.5 stalks per group. 42.5 42.5 42.5 42.5 42.5 42.5 42.5 42.5 42.5 42.5**200 Points**Sam and Michael F. were walking through Farmer Tim’s fields talking about “Canadian Idol” when Sam exclaims “Wow, I see a four leaf cover”. Michael is excited and, searching about the grass, finds three more plants! Soon Sam is on hands and knees eagerly searching for four leaf clovers and is successful in finding two more of these rare mutations. What is the sum of petals on all four leaf clovers found by Sam and Mike on this excellent day?**200 Points**On one glorious spring day Evan and his dog “Fifi” were out strolling in the park. Behold there stood an ice cream vendor who sold Evan a triple fudge brownie deluxe, for a mere 3 dollars and 15 cents. If Evan had forty dollars to begin with, what is the difference between what currency he had to begin his walk and the coinage he spent in procuring an ice cream treat?**Answer**$40 – $3 = $37 $37 - $0.15 = $36.85 The difference between what he had ($40) and what he spent ($3.15) is $36.85.**Answer**Sam 4 leaves on one Micheal 4 leaves on each of three Sam 4 leaves on each of two 4 + 4 + 4 + 4 + 4 + 4 = 24 There were 24 leaves all together.**100 Points**• Which of the following terms is most often found in “division” problems? • Sum • Quotient • Product • Difference ii) What is another common term or descriptor used to indicate division?**Answer**• Quotient • Distribution, division of, doling out, splitting up, allotment, sharing, grouping, sectioning, branching, border off, section off, partition, seperating, how many of …**100 Points**i) Which of the following terms is most often found in addition problems? • Summation • Summer • Sum • Product ii) What is another common term or descriptor used to indicate addition?**100 Points**• Which of the following terms is most often used in “subtraction” problems? • Difference • Desication • Quotient • Summation ii) What is another common term or descriptor used to describe subtraction?**100 Points**• Which of the following terms is most often used in “multiplication” problems? • Sum • Difference • Product • Quotient ii) What is another common term or descriptor used to indicate multiplication within a problem?**Answer**• Product • Increase, growth, groups of, x times y, multiply**Answer**• Difference ii) Taking away, elimination, exclusion, deletion, amputation, confiscation, deduction, ejection**Answer**i) Sum ii) Combining, Adding, Add, Joining, Accumulation, Tallying, Tally, Totting Up, Totalling, Counting**Possible Answer**Kelsey and Emma were out cruising the mall when Emma decided she needed some batteries for her MP3 player. She purchased two packages of batteries. Each cost $6.99 and contain four “AA” batteries. Kelsey found an unused “AA” battery in her coat. How many batteries do they have in total?**800 Points**Write a short convincing math story problem that involves the following symbolic equation: 2 x 4 + 1 This problem is unlimited in time, setting, and characters. You decide.**800 Points**Write a short convincing math story problem that involves the following symbolic equation: 10 + 2 + 1 = 13 This problem is unlimited in time, setting, and characters. You decide.**Possible Answer**Mr. Nicholson began his beginner guitar elective with ten (10) students. The very next elective day another two (2) students joined his elective rather than mountain bike in the rain. On the last day for changes, one more student, Aaron, decided he could use the extra practice and also joined in. When Mr. Nicholson took role call on the third elective day, what were the number of students enrolled in his course?**600 Points**Find the area of the following shape using BEDMAS: 3 m 16 meters 5 meters 4 meters 20 meters**Answer**Area = (Length x width) + (½ base x height) + (side2) rectangle triangle square = (16 m x 5 m) + (16 m x 3 m) ÷ 2 + (4 m)2 = (90 m2) + (48 m2) ÷ 2 + (16 m2) = (90 m2) + (24 m2)+ (16 m2) = 130 m2**400 Points**Jess and Joe worked out their end of term test averages using the method of calcuating mean average. Jess’s Test Results: 60, 70, 70, 80 Joe’s Test Results: 65, 65, 70, 90 Which student averaged higher on their tests. Use BEDMAS to solve.**Answer**Jess: (60 + 70 + 70 + 80) ÷ 4 = 70 Joe: (65 + 65 + 70 + 80) ÷ 4 = 70 Both students score the same result of a mean average of 70%**100 points**B.E.D.M.A.S. is an “acronym” which is a word that typically represents a title or sequence. What does the acronym “BEDMAS” represent?**200 Points**Kaitlyn and Jenna went swimming. Kaitlyn swam 2 laps while Jenna swam three times as many laps as Kaitlyn. How many laps did Kaitlyn and Jenna swim altogether?**Answer**Kaitlyn + Jenna 2 laps + (3 x 2 laps) 2 laps + 6 laps 8 laps The total number of laps swam by Kaitlyn and Jenna would be eight (8).