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I will use square roots to evaluate radical expressions and equations.

Learn how to evaluate square roots in expressions and solve quadratic equations. Explore the concept of radical equations and their applications in real-life scenarios.

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I will use square roots to evaluate radical expressions and equations.

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  1. Objective I will use square roots to evaluate radical expressions and equations. Algebra

  2. Vocabulary • Quadratic Equation - an equation that can be written in standard form as: ax2 + bx + c = 0, where a ≠ 0 • Leading Coefficient - the coefficient (number that precedes) the first term in standard form (x2)

  3. 3 36 + 7 = 3(6) + 7 3 36 + 7 Example 1: Evaluating Expressions Involving Square Roots Evaluate the expression. Evaluate the square root. = 18 + 7 Multiply. = 25 Add.

  4. 2 25 + 4 2 25 + 4 = 2(5) + 4 Guided Practice Evaluate the expression. Evaluate the square root. = 10 + 4 Multiply. = 14 Add.

  5. How to Solve a Quadratic Equation • When b = 0 and the equation is in the form of ax2 + c = 0: • isolate x2 (move c to the other side, then a) • solve for x by finding the square root of both sides of the equation

  6. Summary • Solving x2 = d by finding square roots: • If d > 0, then x2 has two solutions (+, -) • If d = 0, then x2 has one solution (0) • If d < 0, then x2 has no real solutions

  7. Evaluating Radical Equations Solve the equation. Original Problem Take square root of both sides Simplify

  8. Guided Practice Solve the equation.

  9. Evaluating Multi-Step Radical Equations Solve the equation. Original Problem Subtract 4 from both sides Divide both sides by 2 Take square root of both sides Simplify

  10. Guided Practice Solve the equation.

  11. Application: Falling Objects • The height of a falling object can be found using the equation h = -16t2 + s, where h is the height in feet, t is the time in seconds, and s is the initial height in feet. If an object is dropped from 1600 feet, when will it reach the ground?

  12. Application: Falling Objects h = -16t2 + s Equation 0 = -16t2 + 1600 Substitute -1600 = -16t2 Subtract 1600 t2 = 100 Divide t = ±10 Square Root t = 10 seconds Time is positive

  13. Lesson Quiz Solve the equation. 1. x2 = 16 2. x2 + 8 = 152

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