1 / 10

Titration

Titration. Unit 12: Acids and Bases Section 4: Titration. Titration. Titration : The controlled addition and measurement of the amount of a solution of known concentration required to react completely with a measured amount of a solution of unknown concentration

Download Presentation

Titration

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Titration Unit 12: Acids and Bases Section 4: Titration

  2. Titration • Titration: The controlled addition and measurement of the amount of a solution of known concentration required to react completely with a measured amount of a solution of unknown concentration • - It provides a means to determine the concentration of an unknown solution.

  3. Titration • End Point:

  4. Equivalence Point:

  5. Titration Sample Problem In a titration 27.4 mL of 0.0154 M Ba(OH)2 is added to a 20.0 mL sample of HCl solution of unknown concentration until the equivalence point is reached. What is the molarity of the acid solution? Ba(OH)2 + HCl  BaCl2 + H2O

  6. Titration Step One – Balancing Ba(OH)2 + 2HCl BaCl2 + 2 H2O Step Two – Given and Unknown G: 27.4 mL of 0.0154 M Ba(OH)2 20.0 mL of HCl U: # M of HCl

  7. Titration Step Three – Convert M to Mole 1L 1000 mL 0.0154 mol Ba(OH)2 1 L 27.4 mL 4.22 x 10-4 mol Ba(OH)2

  8. Titration Step Four – Convert Ba(OH)2 to mol HCl 2 mol HCL 1 mol Ba(OH)2 4.22 x 10-4 mol Ba(OH)2 8.44 x 10-4 mol HCl

  9. Titration Step Five – Use the mL of HCl to find concentration of HCl 8.44 x 10-4 mol HCl 20.0 mLHCl 1000 mL 1 L 4.22 x 10-2 m HCl

  10. Titration Sample Problem # 2 In a titration 20.0 mL of 5.0 x 10-3 M NaOH is added to a 10.0 mL sample of HCl until equivalence point is reached. What is the molarity of the acid solution? NaOH + HCL  NaCl + H2O

More Related