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Übungen SQL

Übungen SQL. Neue Tabellen. mysql> select * from EMPPROJ; +-------+--------+---------+ | EMPNO | PROJNO | PERCENT | +-------+--------+---------+ | 7369 | 1 | 30 | | 7369 | 2 | 10 | | 7369 | 3 | 20 | | 7499 | 4 | 5 |

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Übungen SQL

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  1. Übungen SQL

  2. Neue Tabellen mysql> select * from EMPPROJ; +-------+--------+---------+ | EMPNO | PROJNO | PERCENT | +-------+--------+---------+ | 7369 | 1 | 30 | | 7369 | 2 | 10 | | 7369 | 3 | 20 | | 7499 | 4 | 5 | | 7499 | 5 | 10 | | 7566 | 1 | 10 | | 7566 | 2 | 10 | | 7566 | 3 | 10 | | 7566 | 4 | 10 | | 7566 | 5 | 10 | | 7788 | 1 | 10 | | 7788 | 2 | 20 | | 7788 | 5 | 10 | +-------+--------+---------+ 13 rows in set (0.00 sec) mysql> select * from PROJECT; +--------+------------+--------+------------+-------+--------+ | PROJNO | PROJNAME | BUDGET | ORT | PLZ | DEPTNO | +--------+------------+--------+------------+-------+--------+ | 1 | Stargate | 100000 | Ulm | 89073 | 20 | | 2 | Terminator | 200000 | Heidenheim | 89520 | 20 | | 3 | Watergate | 500000 | Hamburg | 20095 | 20 | | 4 | Mini | 500 | Hamburg | 20095 | 30 | | 5 | Startup | 5000 | Hamburg | 20095 | 30 | +--------+------------+--------+------------+-------+--------+ 5 rows in set (0.00 sec)

  3. Neue Tabellen, Joins • Mitarbeiter (Namen) des Projekts „Stargate“ • Projekte nach Budget sortiert • Aufsteigend • Absteigend • Mitarbeiter, die an Projekten in „Ulm“ arbeiten • Projekte mit durchführender Abteilung

  4. Aggregate Functions • Mitarbeiter je Projekt (nicht Köpfe, sondern Prozentsatz)select sum(percent) from EMPPROJ group by PROJNO;select p.projname,sum(ep.percent) from EMPPROJ ep, PROJECT p where ep.projno=p.projno group by ep.PROJNO; • Projektbudget je Abteilungselect sum(budget) from PROJECT group by deptno;select d.dname,sum(p.budget) from PROJECT p, DEPT d where p.deptno=d.deptno group by p.deptno; • Mittleres Projektbudget je Abteilung • Ohne Kleinstprojekte (< 1000) • Nur für Abteilungen mit mehr als zwei Projektenselect avg(budget) from PROJECT group by deptno;select avg(budget) from PROJECT where budget > 1000 group by deptno;select avg(budget) from PROJECT group by deptno having (count(*)>2);

  5. weiter • Budget je PLZ-Gebiet (erste Ziffer)select sum(budget) from PROJECT group by left(plz,1); • Mitarbeiter je PLZ-Gebiet (Prozent, nicht Köpfe)select sum(ep.percent) from PROJECT p, EMPPROJ ep where p.projno=ep.projno group by left(p.plz,1); • Mitarbeiter, die in Projekten mitarbeitenselect distinct e.ename from EMP e, EMPPROJ ep where e.empno=ep.empno; • Abteilungen mit mind. Ein SALESMANselect deptno from EMP where job='SALESMAN' group by deptno having count(*) > 1;

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