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Explore the intricate process of energy transformations from chemical to electrical, rotational, and wind energy. Follow the journey of energy conversion through various stages with detailed calculations and efficiencies explained.
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Energy Transformations Arbaaz Khan Quinn Calvert Rishi Savaliya RishantDwivedi
Chemical → Electrical • Chemical= m x SE • m= Mass of Chemical (Kg) • SE= Specific Energy (MJ/Kg) • .045 x 500,000=22500J • 22500J = 22.5KJ • Electrical = IV/t • I= Current (Amps) • V= Voltage (Volts) • t= time (seconds) • (.0038 x 8.52)/.539=.06J Efficiency = .06/22500 = .00267%
Electrical → Rotational • Electrical = .06J • Rotational = ½Iω2 = ½ .0000245(25) = .007656 J • I = Moment of Inertia (kg*m) • Moment of Inertia = mr2 = 0000245 (Kg*m) • m = mass (Kg) • r = radius (meters) • ω = Angular Velocity (revs/s) • Angular Velocity = θ/t = 25 (revs/s) • θ = angular displacement (rads/revs) • t = time (seconds) Efficiency = .00001964/.069 = .0285 %
Rotational → Wind • Rotational Energy = .007656 Joules • Wind Energy == ½(1.172)(3.1293)3()(.035)2 = .69 J • = Air Density (kg*m3) = 1.172 kg*m3 • = Velocity (m/s) = 3.1293 m/s • = Radius (m) = .035m Efficiency = .069/.007656 = 11%
Wind → Kinetic1 • m = mass • v = velocity Efficiency = .00001964/.069 = .0285 %
Potential → Kinetic2 • m = mass • g = acceleration of gravity • h = height • m=mass • v=velocity=x/t • X=Distance • t=time Efficiency = .018/(.557+.00001964) = 3.23%
Overall Efficiency • Efficiency = Wout/Win = .018/(22500+.557) = .00008% • Ein= 22500J • Eout= .018J
References The Engineering Toolbox. (n.d.). Retrieved February 13, 2011, from Engineering Toolbox website: http://www.engineeringtoolbox.com/ Battery energy -- What battery provides more? (n.d.). Retrieved February 17, 2011, from AllAboutBatteries.com website: http://www.allaboutbatteries.com/Battery-Energy.html Lithium. (n.d.). Retrieved February 17, 2011, from Duracell website: http://www1.duracell.com/procell/chemistries/lithium.asp