Area and Perimeter with Algebraic Expressions

1 / 5

# Area and Perimeter with Algebraic Expressions - PowerPoint PPT Presentation

Area and Perimeter with Algebraic Expressions. Vocabulary needed: Formula is an equation used to show a relationship needed in math. Area is the area inside a two-dimensional figure. Perimeter is the distance around a two-dimensional figure.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'Area and Perimeter with Algebraic Expressions' - felicia-munoz

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

Vocabulary needed:

• Formula is an equation used to show a relationship needed in math.
• Area is the area inside a two-dimensional figure.
• Perimeter is the distance around a two-dimensional figure.
• Length is also called the base. It is always perpendicular to the width.
• Width is also called the height.

Example #1

The width of a rectangle is 5 more than half of the length. If the length of the rectangle is 42 feet, what is the area of the rectangle?

Drawing a picture will define your variables.

L= 42

W = ½ L + 5

W = ½ (42) + 5

W = 21 + 5

W = 26 feet

½ L + 5

The area is 1,092 feet squared.

A = LW

A = 42(26)

A = 1,092 feet squared

Example #2

The length of a rectangle is twice the width. If the perimeter of the rectangle is 78 inches, what is the length and the width?

L = 2w

P = 2L + 2W

78 = 2(2w) + 2w

78 = 4w + 2w

78 = 6w

13 = w

Since the length is 2w or 2(13), the length is 26 inches

w

The width of the rectangle is 13 inches and the length is 26 inches.

Example #3

The perimeter of a rectangle is 96 cm. The length of the rectangle is 8 less than triple the width. Find the length and the width of the rectangle.

P = 2L + 2W

96 = 2(3W – 8) + 2W

96 = 6W – 16 + 2W

96 = 8W – 16

112 = 8W

14 = W

L = 3(14) – 8 = 34

L = 3W – 8

W

The width of the rectangle is 14 cm and the length is 34 cm.