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Stoichiometry

Stoichiometry. Stoichiometry. Stoy – key – ohm – e - tree. 9.1 Introduction to Stoichiometry. 1. Define Stoichiometry. 2. Describe the importance of the mole ratio in stoichiometric calculations. 3. Write a mole ratio relating two substances in a chemical equation.

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Stoichiometry

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  1. Stoichiometry

  2. Stoichiometry Stoy – key – ohm – e - tree

  3. 9.1 Introduction to Stoichiometry 1. Define Stoichiometry. 2. Describe the importance of the mole ratio in stoichiometric calculations. 3. Write a mole ratio relating two substances in a chemical equation. 4. Calculate the amount in moles of a reactant or product from the amount in moles of a different reactant or product.

  4. Obj 1: What is Stoichiometry? • Stoichiometry means Stoicheio = element Metron = measure • Stoichiometry is the quantitative study of chemical reactions using balanced equations.

  5. Obj 2: Mole Ratio • Mole Ratios come from the coefficients in a balanced equation. • Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

  6. Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2 2 NH3 The Possible Mole Ratios are:

  7. Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2 2 NH3 The Possible Mole Ratios are: 1 mol N2 1 mol N2 3 mol H2 3 mol H2 2 mol NH3 2 mol NH3

  8. Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2 2 NH3 Other Possible Mole Ratios: 1 mol N2 1 mol N2 3 mol H2 3 mol H2 2 mol NH3 2 mol NH3 3 mol H2 2 mol NH3 2 mol NH3 1 mol N2 1 mol N2 3 mol H2

  9. Obj 4: Using a Mole Ratio 1 N2 + 3 H2 2 NH3 7.5 mol N2? mol H2 ? mol NH3

  10. Obj 4: Using a Mole Ratio 1 N2 + 3 H2 2 NH3 7.5 mol N2? mol H2 ? mol NH3 7.5 mol N2 (3 mol H2 ) = ? (1 mol N2 )

  11. Obj 4: Using a Mole Ratio 1 N2 + 3 H2 2 NH3 7.5 mol N2? mol H2 ? mol NH3 7.5 mol N2 (3 mol H2 ) = 22.5 mol H2 (1 mol N2 )

  12. Using a Mole Ratio 1 N2 + 3 H2 2 NH3 7.5 mol N222.5 mol H2 ? mol NH3 7.5 mol N2 (2 mol NH3) = ? (1 mol N2 )

  13. Obj 4: Using a Mole Ratio 1 N2 + 3 H2 2 NH3 7.5 mol N222.5 mol H2 ? mol NH3 7.5 mol N2 (2 mol NH3) = 15.0 mol NH3 (1 mol N2 )

  14. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: _ N2 + _ H2 _ NH3

  15. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: 2 N2 + 6 H2 4 NH3

  16. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: 2 N2 + 6 H2 4 NH3 • Triple Batch: _ N2 + _ H2 _ NH3

  17. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: 2 N2 + 6 H2 4 NH3 • Triple Batch: 3 N2 + 9 H2 6 NH3

  18. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: 2 N2 + 6 H2 4 NH3 • Triple Batch: 3 N2 + 9 H2 6 NH3 • Half Batch: _ N2 + _ H2 _ NH3

  19. Obj 4: Cookie Stiochiometry • One Batch: 1 N2 + 3 H2 2 NH3 • Double Batch: 2 N2 + 6 H2 4 NH3 • Triple Batch: 3 N2 + 9 H2 6 NH3 • Half Batch: 0.5 N2 + 1.5 H2 1 NH3

  20. Lets Look at Our Problem AgainWe want 7.5 batch ! 1 N2 + 3 H2 2 NH3 __ mol N2 ___ mol H2 __ mol NH3

  21. Lets Look at Our Problem AgainWe want 7.5 batch ! 1 N2 + 3 H2 2 NH3 7.5 mol N2 22.5 mol H2 15.0 mol NH3

  22. The End The Final Curtain

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