1 / 1

E3_2B3

Example 3 Evaluate the Riemann sum R ( P,T,f ) where f ( x ) = arctan x , P = { 0, 1/4, 1/3, 1/2, 3/4, 4/5, 1 } and T = { 1/8, 1/3, 5/12, 3/5, 4/5, 7/8 } . Solution Substitute into the formula

enye
Download Presentation

E3_2B3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Example 3 Evaluate the Riemann sum R(P,T,f)where f(x) = arctan x, P = {0, 1/4, 1/3, 1/2, 3/4, 4/5, 1}and T = {1/8, 1/3, 5/12, 3/5, 4/5, 7/8}. Solution Substitute into the formula R(P,T,f) = f(t1)(x1-x0) + f(t2)(x2-x1) + f(t3)(x3-x2) + f(t4)(x4-x3) + f(t5)(x5-x4) + f(t6)(x6-x5) where x0=0, x1=1/4, x2=1/3, x3=1/2, x4=3/4, x5=4/5, x6=1 and t1=1/8, t2=1/3, t3=5/12, t4=3/5, t5=4/5, t6=7/8: R(P,T,f) = (arctan 1/8)[1/4 – 0] + (arctan 1/3)[1/3– 1/4] + (arctan 5/12)[1/2-1/3] + (arctan 3/5)[3/4-1/2] + (arctan 4/5)[4/5-3/4] + (arctan 7/8)[1-4/5] • (.124)(.25) + (.322)(.083) + (.395)(.167) + (.540)(.25) + (.675)(.05) + (.719)(.200) • .031+ .027+ .066+ .135 + .034 +.144  0.437

More Related