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Homework 4, calculating linkage: 1) You make a test cross from the following cross: R1 r2 / R1 r2 X r1 R2 / r1 R2 PowerPoint Presentation
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Homework 4, calculating linkage: 1) You make a test cross from the following cross: R1 r2 / R1 r2 X r1 R2 / r1 R2

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Homework 4, calculating linkage: 1) You make a test cross from the following cross: R1 r2 / R1 r2 X r1 R2 / r1 R2 You inoculate the progeny with an race that is avirulent on both genes and get 2 susceptible progeny out of 200 test cross progeny. What is the recombination distance?

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Homework 4, calculating linkage:

  • 1) You make a test cross from the following cross: R1 r2 / R1 r2 X r1 R2 / r1 R2
  • You inoculate the progeny with an race that is avirulent on both genes and get 2 susceptible progeny out of 200 test cross progeny. What is the recombination distance?
  • 2) You make a test cross from the following cross: R1 r2 / R1 r2 X r1 R2 / r1 R2 You inoculate the progeny with two races, Race A is virulent on R1 and avirulent on R2, Race B is avirulent on R1 and virulent on R2. You find 95 test cross progeny are resistant to race A and susceptible to race B, 101 test cross progeny that are resistant to race B and susceptible to race A, three progeny that are resistant to both races and one that is susceptible to both. B What is the recombination distance?
  • You find a line you think has both genes: You make a test cross with it, represented by the following cross: R1 R2 / R1 R2 X r1 r2 / r1 r2
  • You inoculate the progeny with two races, Race A is virulent on R1 and avirulent on R2, Race B is avirulent on R1 and virulent on R2. You find 2 test cross progeny are resistant to race A and susceptible to race B, 4 test cross progeny that are resistant to race B and susceptible to race A, 99 progeny that are resistant to both races and 95 that are susceptible to both. B What is the recombination distance?
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4) Estimate the map distance between a disease resistance gene and the DNA marker shown on the two gels below. Parent 1 (P1) is homozygous for the dominant resistance gene (R/R) and parent 2 (P2) is homozygous for the susceptible allele (r/r). The progeny are from a cross between the F1 hybrid (P1 x P2) crossed to P2. R indicates the individual is disease resistant and S indicates it is susceptible. What is you estimate of map distance between the marker and the R gene.

P1 P2 F1 PROGENY

R S R S R S R S S R S S R S R S R R S R

MORE PROGENY

S R S R S S R S S R S R S R R S R R S R R

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5) Estimate the map distance between the dominant gene R, for red seed color, and the DNA marker shown on the two gels below. Parent 1 (P1) is resistant and homozygous for the dominant ‘R’ allele (genotype R/R) and parent 2 (P2) is homozygous for the recessive susceptible allele ‘r’ (r/r). The progeny are from a cross between the F1 hybrid (P1 x P2) crossed to P2. R indicates the individual is resistant. What is you restimate of map distance between the marker and the R gene.

P1 P2 F1 PROGENY

R S R S R S S S S R S S R S R S R R S R

MORE PROGENY

S R S R S S R S S R S R S R R S R R S R R

answers move the green box after you solve no peeking
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Problem 1: 2%

2: 2%

3: 3%

4: 2.6%

5: 10.5 %