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NOTES: Gases, Molar Volume, & Stoichiometry – a REVIEW!

Learn about gases, molar volume, and stoichiometry through examples. Avogadro's hypothesis states that equal volumes of gases at the same temperature and pressure contain equal numbers of particles. Discover how to calculate volumes, molecules, and masses in gas reactions.

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NOTES: Gases, Molar Volume, & Stoichiometry – a REVIEW!

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  1. NOTES: Gases, Molar Volume, & Stoichiometry – a REVIEW!

  2. Avogadro’s Hypothesis: ● equal volumes of gases at the same temperature and pressure contain equal #’s of particles; ● at STP, 1 mol (6.02 x 1023) of particles of any gas occupies a volume of 22.4 L.

  3. Example #1: What volume does 0.742 mol of argon gas occupy at STP?

  4. Example #1: What volume does 0.742 mol of argon gas occupy at STP?

  5. Example #1: What volume does 0.742 mol of argon gas occupy at STP? = 16.6 L

  6. Example #2: How many oxygen molecules are in 3.36 L of oxygen gas at STP?

  7. Example #2: How many oxygen molecules are in 3.36 L of oxygen gas at STP?

  8. Example #2: How many oxygen molecules are in 3.36 L of oxygen gas at STP? = 9.03 x 1022 molecules

  9. Example #3: Determine the volume (in L) occupied by 12.6 g of nitrogen gas, N2, at STP.

  10. Example #3: Determine the volume (in L) occupied by 12.6 g of nitrogen gas, N2, at STP.

  11. Example #3: Determine the volume (in L) occupied by 12.6 g of nitrogen gas, N2, at STP. = 10.0 L N2

  12. Stoichiometry Example #1: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) What mass of water is needed to react with 29.3 L of Li3N?

  13. Stoichiometry Example #1: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) What mass of water is needed to react with 29.3 L of Li3N?

  14. Stoichiometry Example #1: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) What mass of water is needed to react with 29.3 L of Li3N? = 70.6 g H2O

  15. Stoichiometry Example #2: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) When 13.3 L of NH3 are produced how many formula units of LiOH are produced?

  16. Stoichiometry Example #2: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) When 13.3 L of NH3 are produced how many formula units of LiOH are produced?

  17. Stoichiometry Example #2: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) When 13.3 L of NH3 are produced how many formula units of LiOH are produced? = 1.07 x 1023 formula units LiOH

  18. Stoichiometry Example #3: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) Given 112.5 grams of LiOH produced, what volume (L) of Li3N was used?

  19. Stoichiometry Example #3: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) Given 112.5 grams of LiOH produced, what volume (L) of Li3N was used?

  20. Stoichiometry Example #3: Li3N(g) + 3H2O(l) NH3(g) + 3LiOH(aq) Given 112.5 grams of LiOH produced, what volume (L) of Li3N was used? = 35.1 L Li3N

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