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Limiting Reactant. Which will run out first?. Each reactant’s amount will be provided, either in moles or mass Two methods can be used Trial Method Advancement Method. Trial Method.

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## Limiting Reactant

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**Which will run out first?**• Each reactant’s amount will be provided, either in moles or mass • Two methods can be used • Trial Method • Advancement Method**Trial Method**• Use mass-mass stoichiometry calculation to determine how much Reactant B will be required to completely consume Reactant A. • Sample Problem: 15.0g of N2 reacts with 15.0g of H2 to make ammonia according to the equation N2 + 3H2 → 2NH3 • How much ammonia can be made?**Solution to Ex. 1**• Trial method calculation • Advancement Method • Moles of each reactant (n)/coefficient then compare results • N2: 15.0g/28.02g/mol/1mol = 0.535 • H2: 15.0g/2.016g/mol/3mol = 2.48 • Lowest value is ALWAYS LR**And the point is…**• Since it runs out first, the limiting reactant must be determined in order to determine the maximum theoretical yield for this reaction. • How much ammonia (NH3) can be made from these amounts of reactants? • Trial method calculation

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