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Solving Systems of Equations

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Solving Systems of Equations

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    1. Solving Systems of Equations Using Substitution

    2. Example y = 5x + 10 5x + 2y = 80

    3. Isolate either x or y. In this example, y is already by itself in the first equation. y = 5x + 10 5x + 2y = 80

    4. In the second equation, substitute y with 5x+10 5x + 10 5x + 2 = 80

    5. Use the distributive property 5x + 2 (5x + 10) = 80 5x + = 80 5x + 10x + 20 = 80 Simplify 15x + 20 = 80 Combine like terms

    6. Solve for x. 15x + 20 = 80 -20 -20 Subtract 20 from both sides 15x = 60 15 15 Divide both sides by 15 x = 4 First part of your answer!

    7. Now Plug it in…Plug it in! Choose either equation to make a substitution for x = y =5x +10 5x + 2y = 80 y = 5( ) + 10 y = 20 + 10 Multiply 5 and 4 y = 30 Second part of your answer!!

    8. Put your answer together! We found that x = and y = . What does the solution mean? It tells us where the two lines intersect. Your final answer… ( , )

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