Finding the z value. Help for Chapter 5, SHW Problem 7. .0301. .0301. LSL. Mean. USL. X. z = ?. 0. Assume that 6.02% of a company product is defective. Find the z value corresponding to the upper spec. limit. (Use .0602 and split it between
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Help for Chapter 5, SHW Problem 7
z = ?
Assume that 6.02% of a company product is
defective. Find the z value corresponding to the
upper spec. limit. (Use .0602 and split it between
the two tail areas beyond spec limits.)
above USL is .0301 and Appendix B gives the area
between 0 and z, we Look up the area between 0
and z, which is .5000 -.0301. =.4699
z = 1.88
From Appendix B, the z value is z = 1.88. See next
If we know any 3 of the terms in z, we can solve for the 4th. For example, if know z, Mean, and the estimated standard deviation, we can solve for USL.