1 / 14

Acid/Base Review

Acid/Base Review. 1. Identify the Following Properties as a property of an acid, base or both. Contains H+ Contains OH- Has a pH of greater than 7 Is corrosive Bitter taste Sour taste Slippery feel. Acid. Base. Base. Acid and Base. Base. Acid. Base.

dewitt
Download Presentation

Acid/Base Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Acid/Base Review

  2. 1. Identify the Following Properties as a property of an acid, base or both • Contains H+ • Contains OH- • Has a pH of greater than 7 • Is corrosive • Bitter taste • Sour taste • Slippery feel Acid Base Base Acid and Base Base Acid Base

  3. 2. Name the following Acids/Bases • Sulfuric Acid • Hydrosulfuric Acid • H3PO4 • Mg(OH)2 • Potassium hydroxide H2SO4 H2S Phosphoric Acid Magnesium Hydroxide KOH

  4. 3. Complete and Balance the Following Neutralization Reactions • H2SO4 + KOH  • HCl + NaOH  • H3PO4 + LiOH  • H2S + Ca(OH)2  H2SO4 + 2KOH  2H2O + K2SO4 HCl + NaOH  H2O + NaCl H3PO4 + 3LiOH  3H2O + Li3PO4 H2S + Ca(OH)2 2H2O + CaS

  5. 4. Calculate the following pH/pOH • What is the pH of a solution with a [H+]= 2.54 x 10-5? • What is the pOH of a solution with a [H+] = 7.86 x 10-4 • What is the pOH of a solution with a [OH-]= 3.45 x 10-11 pH = -log(2.54 x 10-5) pH = 4.60 pH = -log(7.86 x 10-4) pH = 3.10 14 – 3.10 = pOH pOH = 10.9 pOH = -log(3.45 x 10-11) pOH= 10.5

  6. 5. Calculate the [H+] or [OH-] of the following: • What is the [OH-] of a solution with a pH of 11? • What is the [H+] of a solution with a pH= 4? c. What is the [H+] of a solution with a pOH of 5? 14 – pH = pOH 14 – 11 = 3 [OH-] = 10-3 =1 x 10-3 [H+] = 10-pH [H+] = 10-4 = 1 x 10-4 14 – pOH = pH 14 – 5 = 9 [H+] = 10-9 =1 x 10-9

  7. 6. If it takes 50mL of 0.5 M KOH solution to completely neutralize 125 mL of sulfuric acid solution (H2SO4), what is the concentration of the H2SO4 solution? Step #1: Write out the balanced neutralization reaction. H2SO4 + 2KOH  2H2O + K2SO4 Step #2: Identify the known. 50 mL of 0.5 M KOH

  8. 6. If it takes 50mL of 0.5 M KOH solution to completely neutralize 125 mL of sulfuric acid solution (H2SO4), what is the concentration of the H2SO4 solution? Step #3: Use the known volume and molarity to calculate the moles of the known.

  9. 6. If it takes 50mL of 0.5 M KOH solution to completely neutralize 125 mL of sulfuric acid solution (H2SO4), what is the concentration of the H2SO4 solution? H2SO4 + 2KOH  2H2O + K2SO4 Step #4: Use the molar ratio to convert from known moles to unknown moles.

  10. 6. If it takes 50mL of 0.5 M KOH solution to completely neutralize 125 mL of sulfuric acid solution (H2SO4), what is the concentration of the H2SO4 solution? Step #5: Use the calculated value of the unknown moles and the volume of unknown to determine the concentration.

  11. 7. If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? Step #1: Write out the balanced neutralization reaction. HCl + NaOH  H2O + NaCl Step #2: Identify the known. 25 mL of 0.05 M HCl

  12. 7. If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? Step #3: Use the known volume and molarity to calculate the moles of the known.

  13. 7. If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? HCl + NaOH  H2O + NaCl Step #4: Use the molar ratio to convert from known moles to unknown moles

  14. 7. If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? Step #5: Use the calculated value of the unknown moles and the volume of unknown to determine the concentration.

More Related