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Photochemical kinetics PowerPoint Presentation
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Photochemical kinetics - PowerPoint PPT Presentation


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Photochemical kinetics. Intensity. Transmittance. Absorbance. Why LOG?. Transmittance. Absorbance. Beer’s Law. dP( x )/dx = - κ P( x ).  P( x ) = exp(- κ x ). Beer’s law. Cross section ~10 -18 cm 2. Molar extinction Coefficient ~250 L.mol -1 cm -1. ε = 313 M -1 cm -1

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Presentation Transcript
slide5

Transmittance

Absorbance

Why LOG?

slide6

Transmittance

Absorbance

Beer’s Law

slide7

dP(x)/dx = -κ P(x)

P(x) = exp(-κx)

slide9

Cross section

~10-18 cm2

Molar extinction

Coefficient

~250 L.mol-1cm-1

slide11

ε = 313 M-1 cm-1

b = 2 cm

T = 3.16% = 0.0316

A = -logT = 1.50

c = 1.5/(313 M-1) (2 cm-1) = 0.0024 M

slide12

NB 1: Beer fails when

photochemistry happens

NB 2: The photophysics

Is hidden in σ

(So we haven’t done much yet)

slide16

Photochemical kinetics

STEADY STATE

HYPOTESIS

slide17

Photochemical kinetics

Ozone production

λ≤ 240 nm

λ≤ 280 nm

slide20

Steady state hypothesis: d[O]/dt = 0

  • Solve for [O]
  • Plug into disappearance rate of [O3]