10.5 Law of Cosines. Obj : ____________________ ________________________. For any triangle ABC with sides a, b, and c. a 2 = b 2 + c 2 – 2bc cos A b 2 = a 2 + c 2 – 2ac cos B c 2 = a 2 + b 2 – 2ab cos C. You can use the Law of Cosines to solve a triangle if:
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a2 = b2 + c2 – 2bc cos A
b2 = a2 + c2 – 2ac cos B
c2 = a2 + b2 – 2ab cos C
2 sides and the included angle
Points A and B are on opposite site sides of Lake Hoorah. From a 3rd point, C, the angle between the lines of sight to point A and B measures 46°. If the distance from A to C is 350 meters, and the distance from B to C is 286 meters what is the distance from A to B?