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課題 ３

課題 ３. | x |=3, | y |=2, | z |=5 であるから | xyz |=| x |+| y |+| z |=12 , | x e y e z e |=| x | +| e | +| y | +| e | +| z | +| e | = 12 , | x j y k z l |= j * | x |+ k *| y |+ l *| z |=3 j +2 k +5 l 2. A ={ a,b }, B ={ b,c,d } とする とき AAB= ( AA ) B = { aa, ab, ba , bb } B

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課題 ３

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  1. 課題３ • |x|=3, |y|=2, |z|=5 であるから |xyz|=|x|+|y|+|z|=12, |xeyeze|=|x|+|e|+|y|+|e|+|z|+|e|=12, |xjykzl|=j*|x|+k*|y|+l*|z|=3j+2k+5l 2. A={a,b}, B={b,c,d}とするとき • AAB=(AA)B = {aa, ab, ba, bb}B = { aab, abb, bab, bbb, aac, abc, bac, bbc, aad, abd, bad, bbd } • {w∈A* | |w| < 5}= • {e, a, b, aa, ab, ba, bb, aaa,aab,aba,abb,baa,bab,bba,bbb, aaaa,aaab,abaa,abab,abba,abbb,baaa,baab,baba,babb, bbaa,bbab,bbba,bbbb}

  2. 3 . V={0,1,2,3,4,5,6,7}, E={i→j | i, j ∈ V, j = i2%8 }とするとき、 iと、i2%8の値となるjを左表で調べて結ぶことにより右図を得る。 7 1 0 6 2 5 4 3

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