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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz.

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Presentation Transcript
slide1

TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary.

Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then

be taken to the post-quiz.

CLICK TO CONTINUE

slide2

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

The element sulfur,S(s), contains 6.022 x 1023S atoms/mole.

The compound bromine, Br2(l), contains 6.022 x 1023Br2 molecules/mole.

The compound carbon dioxide, CO2(g), contains 6.022 x 1023 CO2 molecules/mole .

CLICK TO CONTINUE

slide3

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

S(s) = 32.066 g/mol

Br2(l) = 159.808 g/mol

CO2(g) = 44.010 g/mol

CLICK TO CONTINUE

slide4

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

At room temperature and pressure:

S(s)  16 cm3/mol

Br2(l)  51 cm3/mol

CO2(g)  2 x 104 cm3/mol

CLICK TO CONTINUE

slide5

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

sulfur atoms, S

atomic weight = 32.066

 32.066 g S/mol S

bromine molecules, Br2

atomic weight = 79.904  molecular weight

159.808  159.808 g Br2/mol Br2

carbon dioxide molecules, CO2

atomic weights

carbon 12.011, oxygen 15.9994

molecular weight 44.010 

44.010 g CO2/mol CO2

CLICK TO CONTINUE

slide6

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

  • Convert 30 g carbon to moles.

C: atomic weight 12.011

12.011 g C/mol C

CLICK TO CONTINUE

slide7

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(Convert 30 g C to mol.)

mass (g) carbon  moles carbon

CLICK TO CONTINUE

slide8

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(Convert 30 g C to mol.)

1 12.011

mole C

g C

_________

x

30 g C

30 mole C

12.011

= 2.5 mol C

CLICK TO CONTINUE

slide10

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(Convert 3.5 L NH3 at S.T.P. to mol.)

22.414 L/mole NH3(g)

(at S.T.P.)

volume (L) ammonia 

moles ammonia

CLICK TO CONTINUE

slide11

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(Convert 3.5 L NH3 at S.T.P. to mol.)

mol NH3

L NH3

1

22.414

___________

3.5 L NH3

x

3.5 mol NH3

22.414

= 0.16 mol NH3

CLICK TO CONTINUE

slide12

3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution?

M (molar) = mol solute/L solution

0.5 M glucose = 0.5 mol glucose/1 L soln

slide13

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# mol glucose in 10 mL 0.5 M soln?)

volume (mL) solution  volume (L) solution  moles solvent

CLICK TO CONTINUE

slide14

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# mol glucose in 10 mL 0.5 M soln?)

1

1000

or

10 mL solutionx 1 L

103 mL

L

mL

______

10 mL solution

x

or

10 mL solutionx 10-3 L

1 mL

CLICK TO CONTINUE

slide15

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# mol glucose in 10 mL 0.5 M soln?)

x mol glucose L solution

0.5

1

10 mL solutionx 1 L

1000 mL

or 10 mL solutionx 1 L 103 mL

or 10 mL solutionx 10-3 L 1 mL

x mol glucose L solution

0.5

1

x mol glucose L solution

0.5

1

CLICK TO CONTINUE

slide16

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# mol glucose in 10 mL 0.5 M soln?)

10 mL solutionx 1 L x 0.5 mol glucose

1000 mL 1 L solution

or

10 mL solutionx 1 L x 0.5 mol glucose 103 mL 1 L solution

or

10 mL solutionx 10-3L x 0.5 mol glucose 1 mL 1 L solution

CLICK TO CONTINUE

slide17

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# mol glucose in 10 mL 0.5 M soln?)

10 x 0.5 mol glucose

1000

or

10 x 0.5 mol glucose

103

or

10 x 10-3 x 0.5 mol glucose

= 0.005 or 5 x 10-3 mol glucose

CLICK TO CONTINUE

slide18

4. How many atoms are

present in 4.0 moles of phosphine, PH3?

slide19

(# atoms in 4.0 mol PH3?)

4.0 atoms/molecule PH3

moles phosphine  molecules phosphine  atoms

CLICK TO CONTINUE

slide20

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# atoms in 4.0 mol PH3?)

6.02 x 1023

1

molecules PH3 mol PH3

4.0 mol PH3

x

_____________________

x atoms

molecule PH3

4 1

CLICK TO CONTINUE

slide21

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# atoms in 4.0 mol PH3?)

___________________

4.0 mol PH3x 6.02 x 1023molecules PH3

1 mol PH3

x 4 atoms

1 molecules PH3

4.0 x 6.02 x 1023 x 4 atoms

= 9.6 x 1024 atoms

CLICK TO CONTINUE

slide23

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# electrons lost by 0.65 mol Ca?)

CaCa2+ + 2e

moles calcium  atoms calcium  electrons

CLICK TO CONTINUE

slide24

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# electrons lost by 0.65 mol Ca?)

6.02 x 1023

1

atoms Ca

mol Ca

__________________

0.65 mol Ca

x

x electrons atom Ca

2

1

CLICK TO CONTINUE

slide25

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

(# electrons lost by 0.65 mol Ca?)

0.65 mol Ca x 6.02 x 1023 atoms Ca 1 mol Ca x 2 electrons 1 atom Ca

0.65 x 6.02 x 1023 x 2 electrons

= 7.8 x 1023 electrons

CLICK TO CONTINUE

END OF TUTORIAL

slide26

RETURN TO TUTORIAL

OR

GO TO POST-QUIZ