Impedance Transformation

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# Impedance Transformation - PowerPoint PPT Presentation

Impedance Transformation. Resistance of Inductor. R= R sh (L/W) R sh is the sheet resistance Rsh is 22 mOhms per square for W=6um. If the outer diameter is 135 um, the length is approximately 135um x4=540 um. R=22 mOhms x (540/6)=1.98 Ohms.

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### Impedance Transformation

Resistance of Inductor
• R=Rsh(L/W)
• Rsh is the sheet resistance
• Rsh is 22 mOhms per square for W=6um.
• If the outer diameter is 135 um, the length is approximately 135um x4=540 um.
• R=22 mOhms x (540/6)=1.98 Ohms

Q=(ωL)/R=(2π2.4G0.336 nH)/1.98 Ω=2.56

Include Resistor In the Tank Circuitry

Q=2.427/(3.076-1.888)=2.04

Inclusion of parasitic resistance

reduces the circuit Q from 10.

Problem
• The gain drops significantly when the resistive loss in the inductor is accounted for.
Assignment
• Redesign the circuit so that it meet the following specifications:
• fo=2.4 GHz
• Q(circuit quality factor)>7
• Av=Vout/Vin=-6 dB
• Rs=50 Ohms
Design Constraints
• Design constratins:
• Av=Rp/(Rs+Rp)
• Rp=Rind(1+Qind*Qind)
• Qcirc=ωo(Rp*Rs/(Rp+Rs))C=ωoAvRsC
• ωo=1/sqrt(LC)
• Qind=ωoL/Rind
Submission Check List
• Determine the Qind that achieves the Av.
• Submit the circuit schematic
• Submit AV as a function of frequncy from 1M to 10 GHz.