acids bases equilibria part iv analysis of salts n.
Download
Skip this Video
Loading SlideShow in 5 Seconds..
Acids – Bases Equilibria Part IV: Analysis of Salts PowerPoint Presentation
Download Presentation
Acids – Bases Equilibria Part IV: Analysis of Salts

Loading in 2 Seconds...

play fullscreen
1 / 10

Acids – Bases Equilibria Part IV: Analysis of Salts - PowerPoint PPT Presentation


  • 185 Views
  • Uploaded on

Acids – Bases Equilibria Part IV: Analysis of Salts. Jespersen Chap. 17 Sec 6. Dr. C. Yau Spring 2013. SALT SOLUTIONS HCl + NaOH H 2 O + NaCl water salt We say that HCl has been neutralized by NaOH. The product mixture is neutral. HCl + NH 4 OH H 2 O + NH 4 Cl

loader
I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
capcha
Download Presentation

Acids – Bases Equilibria Part IV: Analysis of Salts


An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
    Presentation Transcript
    1. Acids – Bases EquilibriaPart IV: Analysis of Salts Jespersen Chap. 17 Sec 6 Dr. C. Yau Spring 2013

    2. SALT SOLUTIONS HCl + NaOH H2O + NaCl water salt We say that HCl has been neutralized by NaOH. The product mixture is neutral. HCl + NH4OH H2O + NH4Cl water salt The product mixture is acidic! Why? NH4Cl dissociates into NH4+ and Cl- and NH4+ is slightly acidic! NH4+ + H2O NH3 + H3O+

    3. In the same way, HC2H3O2 + NaOH H2O + NaC2H3O2 The product mixture is not neutral. NaC2H3O2 dissociates into Na+ and C2H3O2- and acetate is the conjugate base of a weak acid (acetic acid). C2H3O2- is a relatively strong base. It will pull a proton off water: C2H3O2- + HOH HC2H3O2 + OH- producing OH- ions. THUS SODIUM ACETATE PRODUCES A SLIGHTLY BASIC SOLUTION!

    4. Predicting Acid–Base Properties Of A Salt 1. If neither the cation nor the anion can affect the pH, the solution should be neutral. 2. If only the cation of the salt is acidic, the solution will be acidic. 3. If only the anion of the salt is basic, the solution will be basic. 4. If a salt has a cation that is acidic and an anion that is basic, the pH of the solution is determined by the relative strengths of the acid and base. Compare Ka and Kb for the ions

    5. Predicting Effects Of Ions On pH Most metal cations are neutral or extremely weak acids (e.g. Na+, Ca2+) Conjugate acids of weak bases are acidic (e.g. NH3, N2H4 NH4+, N2H5+) Conjugate bases of weak acids are basic (e.g. HC2H3O2, HNO2  C2H3O2¯, NO2¯) Conjugate bases of the strong acids are neutral (except HSO4- which is still fairly acidic) (e.g. HCl, HNO3  Cl¯, NO3¯) but not H2SO4 HSO4¯

    6. 0.1M solutions of the following are acidic basic/ neutral or amphoteric? … HCl NaCl NaCN NH4Cl HCN NaClO4 Na3PO4 • acidic • neutral • Basic • acidic • acidic • neutral • basic Do p. 795: Pract Exer 25 & 26.

    7. At this point you are expected to recognize whether a salt will produce an acidic or basic solution from looking at its formula. That is a qualitativeanalysis. We now examine how to analyze the pH of salt solutions quantitatively. Decide whether cation or anion will affect pH. Write eqn for the Ka or Kb of ion. Calc Ka or Kb from Kb or Ka of its conjugate acid/base Set up ICE table. CalcpH.

    8. Example 17.5 p. 796 What is the pH of a 0.10 M solution of NaOCl? For HOCl, Ka = 3.0x10-8 Example What is the pH of a 0.20 M solution of hydrazinium chloride N2H5Cl? Hydrazine N2H4 is a weak base with Kb = 9.6x10-7 Do Pract Exer 27, 28 & 29 p. 797

    9. Example Will an aqueous solution that is 0.20 M NH4F be acidic, basic or neutral? Do Pract Exer 30 & 31 p.798

    10. Summary of what we did in the previous examples Example 17.5: Calculation for pH of salt made from strong base and weak acid (NaOCl). Example with N2H5Cl. : Calculation for pH of salt made from weak base and strong acid ExampleNH4F: Analysis of salt made from weak base and weak acid.