EXAMPLE 1

1 / 10

# EXAMPLE 1 - PowerPoint PPT Presentation

The free-throw lane on an international basketball court is shaped like a trapezoid. Find the area of the free-throw lane. Find the area of a trapezoid. EXAMPLE 1. BASKETBALL. 1. A = h(b 1 + b 2 ). 2. 1. = (5.8)(3.6 + 6). 2. ANSWER.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'EXAMPLE 1' - colleen

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

The free-throw lane on an international basketball court is shaped like a trapezoid. Find the area of the free-throw lane.

Find the area of a trapezoid

EXAMPLE 1

1

A = h(b1 + b2)

2

1

= (5.8)(3.6 + 6)

2

The area of the free-throw lane is about 27.8 square

meters.

Find the area of a trapezoid

EXAMPLE 1

SOLUTION

The height of the trapezoid is 5.8 meters. The lengths of the bases are 3.6 meters and 6 meters.

Formula for area of a trapezoid

Substitute 5.8 for h, 3.6 for b1, and

6 for b2.

= 27.84

Simplify.

Rhombus PQRSrepresents one of the inlays on the guitar in the photo. Find the area of the inlay.

Find the area of a rhombus

EXAMPLE 2

MUSIC

Find the area of a rhombus

EXAMPLE 2

SOLUTION

STEP 1

Find the length of each diagonal. The diagonals of a rhombus bisect each other, so QN = NSand PN = NR.

QS = QN + NS = 9 + 9 = 18 mm

PR = PN + NR = 12 + 12 = 24 mm

STEP 2

Find the area of the rhombus. Let d1 represent QSand d2represent PR.

1

A = d1d2

2

1

= (18)(24)

2

The area of the inlay is 216square millimeters.

Find the area of a rhombus

EXAMPLE 2

Formula for area of a rhombus

Substitute.

= 216

Simplify.

1.

for Examples 1 and 2

GUIDED PRACTICE

Find the area of the figure

SOLUTION

The height of the trapezoid is 4ft. The lengths of the bases are 6ftand 8ft.

1

A=h(b1+b2)

2

1

= (4)(6 + 8)

2

The area of the figure is 28ft2.

for Examples 1 and 2

GUIDED PRACTICE

Formula for area of a trapezoid

Substitute 4 for h, 6 for b1, and

8 for b2.

= 28

Simplify.

2.

area of kite is 42 in2.

1

A = h(b1 b2)

2

1

= (6)(14)

2

for Examples 1 and 2

GUIDED PRACTICE

SOLUTION

Formula for area of kite

Substitute.

= 42

Simplify.

3.

for Examples 1 and 2

GUIDED PRACTICE

SOLUTION

STEP 1

Find the length of each diagonal. The diagonals of a rhombus bisect each other,

= 30 + 30

= 60 m

d1

d2

= 40 + 40

= 80 m

1

A =d1d2

2

1

= 60 80

2

The area of rhombus is2400 m2.

for Examples 1and 2

GUIDED PRACTICE

STEP 2

Find the area of the rhombus.

Formula for area of a rhombus

Substitute.

= 2400

Simplify.