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Welcome to Physics. A baseball leaves the bat with an upward Velocity of 41.3 m/s. What is its velocity when it reaches an elevation of 60. m above the bat? Use the acceleration of gravity to be 9.8 m/s/s. Vf 2 = Vi 2 + 2aX |Vf| = ( Vi 2 + 2aX )
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A baseball leaves the bat with an upward Velocity of 41.3 m/s. What is its velocity when it reaches an elevation of 60. m above the bat? Use the acceleration of gravity to be 9.8 m/s/s. Vf2 = Vi2 + 2aX |Vf| = (Vi2 + 2aX) = ((41.3 m/s)2 + 2(-9.8 m/s/s)(60. m)) = 23 m/s Vf = +/- 23 m/s +/- 23 m/s
Start Basic Problem Solving Is it Bigger than Your Mouth? Yes Cut it up a bit No Eat it Done
Start Basic Problem Solving Write down given quantities Are you done yet? No Apply any formula Yes Circle the answer
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General Physics: • Linear kinematics • 2D motion • Forces • Energy • Momentum • Circular Motion • Waves and Sound
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