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Monday • June 6th
IMPORTANT INFORMATION You will be taking the iReady Diagnostic this Wednesday & Thursday in class. Be sure you have your chromebook and charger. 01 02 If you were absent on Friday you need to schedule a time to make up Quiz #2. Your Math Quarterly Assessment will be on Tuesday, June 14th. If you are absent please be sure to check Brightspace so you can review the Lesson Slides. 03 04
Directions: Solve the problems below and round your answer to the nearest tenth. Use 3.14 for pi. 1. 2. A circular flower bed has a diameter of 7 meters. Work out the area of the flower bed. Round your answer to the nearest tenth place. The cylinder above has a diameter of 6 inches. What is the area of the base? What is the volume of the image? F:S:S:L: F:S:S:L: F:S:S:L:
Directions: Solve the problems below and round your answer to the nearest tenth. Use 3.14 for pi. 1. 2. Diameter- 7 m Radius- 3.5 m • Answer Key A circular flower bed has a diameter of 7 meters. Work out the area of the flower bed. Round your answer to the nearest tenth place. The cylinder above has a diameter of 6 inches. What is the area of the base? What is the volume of the image? F: πr2S: 3.14 (3.5)2S: 3.14 (12.25)L: 38.5 square meters F: πr2S: 3.14 (3)2S: 3.14 (9)L: 28.3 square inches F: πr2 hS: 3.14 (3)2 7S: 3.14 (9) (7)L: 197.8 cubic inches
4 cm Volume of a Cone 12 cm Formula: V = 1/3Bh or V = 1/3πr2h 9 cm Examples: Calculate the Volume. ex.1) ex.2) V = 1/3πr2h C =1/3 πr2h V= 1/3π42•9 V= 1/3π62•15 V= 1/3π16•9 V= 1/3π62•15 V= 1/3π•16•9 V=1/3 π•36•15 V= 1/348π cm3 V= 180π cm3 V≈ 150.8 cm3 V ≈ 565.49 cm3 15 cm d = Diameter r = Radius h = Height B = Area of the base.
Find the Volume: V = 1/3Bh V= 1/3πr2h 9 in. 12 in.
Find the Volume: V = 1/3Bh V= 1/3πr2h 9 in. Step 1: find the area of the base. Remember: What shape is your base? 12 in.
Find the Volume: V = 1/3Bh V= 1/3πr2h 9 in. 9 in. Step 1: find the area of the base. Remember: What shape is your base. 12 in.
Find the Volume: V = 1/3Bh V= 1/3πr2h 9 in. 9 in. Step 1: find the area of the base. Remember: What shape is your base. Circle: remember how to find the area? A= πr2 12 in. A = 3.14•92 A= 3.14 •81 A = 254.34
Find the Volume: V = 1/3Bh V= 1/3πr2h Step 2: Substitute your answers into the formula. 9 in. 9 in. A= ⅓ 254.34•12 12 in.
Find the Volume: V = 1/3Bh V= 1/3πr2h Step 2: Substitute your answers into the formula. 9 in. 9 in. A= ⅓ 254.34•12 V = ⅓ 3052.08 12 in.
Find the Volume: V = 1/3Bh V= 1/3πr2h Step 2: Substitute your answers into the formula. 9 in. 9 in. A= ⅓ 254.34•12 V = ⅓ 3052.08 V ≈1017.36 in3 12 in.
16155.31 m3 8772.1 m3
16155.31 m3 118,164.5 in3 8772.1 m3
16155.31 m3 118,164.5 in3 8772.1 m3 9110.2 ft3
16155.31 m3 118,164.5 in3 8772.1 m3 9110.2 ft3 30746.9 ft3
16155.31 m3 118,164.5 in3 8772.1 m3 177,020.6 m3 9110.2 ft3 30746.9 ft3
70160.16 in3 56520 cm3
70160.16in3 9679.6 cm3 56,520 cm3
70160.16in3 9679.6 cm3 56520 cm3 237,735.7 mm3
V = ⅓ (πr2)h V = ⅓ (π62)5
V = ⅓ (πr2)h V = ⅓ (π62)5 V= ⅓ (3.14•36)5
V = ⅓ (πr2)h V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2
V = ⅓ (πr2)h V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π72•7.2) V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π72•7.2) V = ⅓ (π•49•7.2) V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π72•7.2) V = ⅓ (π•49•7.2) V = ⅓ (π•352.8) V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π72•7.2) V = ⅓ (π•49•7.2) V = ⅓ (π•352.8) V = ⅓ (1,107.792) V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = ⅓ (π72•7.2) V = ⅓ (π•49•7.2) V = ⅓ (π•352.8) V = ⅓ (1,107.792) V = 369.3 ft3 V = ⅓ (π62)5 V= ⅓ (3.14•36)5 V= ⅓ •565.2 V= 188.4 cm3
V = ⅓ (πr2)h V = ⅓ (πr2)h
V = ⅓ (πr2)h V = ⅓ (πr2)h V = 23.079 yd3
V = ⅓ (πr2)h V = ⅓ (πr2)h V = 23.079 yd3 V = 127.17 in3
V = ⅓ (πr2)h V = ⅓ (πr2)h
V = ⅓ (πr2)h V = ⅓ (πr2)h V= 406.1904 ft3
V = ⅓ (πr2)h V = ⅓ (πr2)h V= 406.1904 ft3 V= 12057.6 mmft3
V = ⅓ (πr2)h V = ⅓ (πr2)h
V = ⅓ (πr2)h V = ⅓ (πr2)h V= 89.019 yd3
V = ⅓ (πr2)h V = ⅓ (πr2)h V= 89.019 yd3 V= 122.5071 in3