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Thursday • Thursday April 21st
Name: ___________________________ Warm-Up 2. If you place a 39-foot ladder against the top of a 34-foot building, how many feet will the bottom of the ladder be from the bottom of the building? Round to the nearest tenth of a foot. You can draw a picture to help. 3. You start driving west for 8 miles, turn left, and drive south for another 11 miles. At the end of driving, what is your straight line distance from your starting point? Round to the nearest tenth of a mile. You can draw a picture to help. • Which of the following sets of numbers could represent the 3 sides of a right triangle?
Answer Key The bottom of the ladder will be 19.1 ft from the bottom of the building.
Answer Key At the end of driving, you are 13.6 mi from your starting point.
Steps to follow with word problems: Step 1: Draw a picture. Step 2: Fill in the given information on the picture. Step 3: Identify the Legs and Hypotenuse. Step 4: Substitute the legs and Hypotenuse in to the formula. Step 5: Solve
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base?
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Step 1: Draw a picture. 2nd X base Home X plate
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Step 1: Draw a picture. 2nd X base 90 ft. Step 2: Fill in the given informtion on the picture. 90 ft. Home X plate
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Step 1: Draw a picture. LEGS 2nd X base 90 ft. Step 2: Fill in the given informtion on the picture. Hypotenuse 90 ft. LEGS Home X plate
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Step 1: Draw a picture. LEGS 2nd X base 90 ft. Step 2: Fill in the given information on the picture. Hypotenuse 90 ft. Step 3: Identify the Legs and Hypotenuse. LEGS Home X plate
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Formula: a2 + b2 = c2 902 + 902 = c2 Step 4: Substitute the legs and Hypotenuse in to the formula.
Let’s try one together. A baseball diamond is a square that is 90 ft on each side. What is the distance a catcher has to throw the ball from home to second base? Formula: a2 + b2 = c2 902 + 902 = c2 8100 + 8100= c2 16200 = c2 16200 = c2 127.3 ft (rounded to nearest tenth) Step 4: Substitute the legs and Hypotenuse in to the formula. Step 5: Solve
Let’s try another one. A 35-foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building. How far above the ground is the point where the ladder touches the building?
Let’s try another one. A 35-foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building. How far above the ground is the point where the ladder touches the building?
Let’s try another one. A 35-foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building. How far above the ground is the point where the ladder touches the building?
Let’s try another one. A 35-foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building. How far above the ground is the point where the ladder touches the building? Formula: a2 + b2 = c2 212 + b2=352 441 + b2 = 1225 -441 = -441 28 feet above the ground. b2 = 784 b = 784 b = 28 ft
Here is a tricky one for you. Two friends start from the same spot with one walking south and the other one walks east. After twenty minutes they are 1.3 miles apart. If the first friend only traveled 0.5 miles, how far did the second friend go?
Here is a tricky one for you. Two friends start from the same spot with one walking south and the other one walks east. After twenty minutes they are 1.3 miles apart. If the first friend only traveled 0.5 miles, how far did the second friend go?
Here is a tricky one for you. Two friends start from the same spot with one walking south and the other one walks east. After twenty minutes they are 1.3 miles apart. If the first friend only traveled 0.5 miles, how far did the second friend go? 1.3 0.5
Here is a tricky one for you. Two friends start from the same spot with one walking south and the other one walks east. After twenty minutes they are 1.3 miles apart. If the first friend only traveled 0.5 miles, how far did the second friend go? Formula: a2 + b2 = c2 0.52 + b2= 1.32 0.25+ b2 = 1.69 -0.25 = -0.25 b2 = 1.44 b = 144 b = 1.2 miles The second friend walked 1.2 miles 1.3 0.5
Practice Problems Pythagorean Theorem: Real-World Problems
Answers: Real-World Problems
If you would like to print the answers to the worksheet, click here. Click here to watch a video of the practice problems being solved and explained. MAKE NEW VIDEO Answers - Pythagorean Theorem Answers to Practice Problems
New Material I can use the Pythagorean Theorem in solving real world problems. The lesson will explain: • using the Pythagorean Theorem • how to find missing sides • a review of equations and square roots If you would like to print the worksheet to use while watching the video, click here.
New Material I can use the Pythagorean theorem to solve real world problems. Click here to view the notes video.
Notes- Pythagorean Theorem Worksheet to use with video
Notes - Pythagorean Theorem Worksheet to use with video
If you would like to print the practice worksheet click here. Pythagorean Theorem Real-World Problems Practice Problems If you do not want to print out the pages, the following slides show the problems and answers to the practice worksheet.
If you would like to print the answers to the worksheet, click here. Otherwise, the answers with some explanations are on the next several slides. Click here to watch a video of the practice problems being solved and explained. Answers - Pytheragean Thersom used to solve real world problems. Answers to Practice Problems
5² x² 13² 28² 45² x² 8² x² 17² X = 12 X = 53 X = 15
