√λ. √λ. V ( f ) = ½ 2 + ¼ 4. . A translation f (x) = f 0 + u (x) → u (x) ≡ f (x) – f 0. selects one of the minima by moving into a new basis. redefining the functional form of f in the new basis ( in order to study deviations in energy from the minimum f 0 ).
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√λ
√λ
V(f) = ½2 + ¼4

A translation f(x) = f0 + u(x)→ u(x) ≡ f(x) – f0
selects one of the minima by moving into a new basis
redefining the functional form of f in the new basis
(in order to study deviations in energy from the minimum f0)
V(f) = V(u+f0) = ½(u+f0)2 + ¼ (u+f0)4
= V0+u2+ √ u3+ ¼u4
plus new self
interaction terms
The observable field describes
particles of ordinary mass m/2.
energy scale
we can neglect
U
1
some calculus of variations
Letting = *
= 0
U
2
= 0
Extrema occur not only for
but also for
But since = *
This must mean2 > 0
2 < 0
> 0
and I guess we’ve sort of been assuming
was a mass term!
defines a circle of radius
 /
in the 2vs1 plane
Furthermore, from
1
U
1
not xy “space”
we note
2U
12
which at = 0gives just2
< 0
making = 0the location of a local MAXIMUM!
circular valley/rut of radius v =
2
1
This clearly shows the U(1)SO(2)
symmetry of the Lagrangian
But only one final state can be “chosen”
Because of the rotational symmetry all are equivalent
We can chose the one that will simplify our expressions
(and make it easier to identify the meaningful terms)
shift to the
selected ground state
expanding the field about the ground state:1(x)=+(x)
L=½11 + ½22
½12+22 ¼12+22
with these substitutions:
v =
L=½ + ½
½2+2v+v2+2
¼2+2v+v2+2
becomes
L=½ + ½
½2+ 2 v ½v2
¼2+2 ¼22+22v+v2
¼2v+v2
v2+2¼2+2 + ¼v4
½ ½(2v)2
Explicitly expressed in
real quantities and v
this is now an ordinary
mass term!
“appears” as a scalar (spin=0)
particle with a mass
½
“appears” as a massless scalar
There is NO mass term!
LOCAL GAUGE TRANSFORMATIONS
D=+igG
Let’s not worry about the
higher order symmetries…yet…
free field for the gauge
particle introduced
Recall: F=GG
* 12 + i22
again we define: 1 + i2
[+ v22] + [ ] + [ FF+ GG] gvG
1
2
g2v2
2
1
2
1
4
+{
g2
2
gG[] + [2+2v+2]GG
2
1
2
+ [2v3+v4+2v2
 (4+43v+62v2+4v3+4v2
+ 222+2v22+v4 + 4 ) ]}
L= [+ v22] + [ ] + [ FF+ GG] gvG
1
2
g2v2
2
1
2
1
4
+{
g2
2
gG[] + [2+2v+2]GG
4
2
1
2
 [4v(3+2)
+ [ v4]
+ [4+222+ 4]
and many interactions
between and
which includes a
numerical constant
v4
4
a whole bunch
of 34 legged
vertex couplings
massless
scalar
free Gauge
field with
mass=gv
scalar field
with
L =
gvG +
+
+
But no MASSLESS
scalar particle has
ever been observed
is a ~massless spin½ particle
is a massless spin1particle
spinless,have plenty of mass!
plus  gvG seems to describe
G
( some QM oscillation
between mixed states?)
Higgs suggested:have not correctly identified the
PHYSICALLY OBSERVABLE fundamental particles!
i.e. it can be equivalently expressed
under any gauge transformation in the complex plane
Note:
or
/=(cos + isin )(1 + i2)
=(1cos2sin ) + i(1sin+ 2cos)
With no loss of generality we are free to pick the gaugea ,
for example, picking:
/2 0 and/ becomes real!
With real, the field vanishes and our Lagrangian reduces to
introducing a MASSIVE Higgs scalar field, ,
and “getting” a massive vector gauge field G
Notice, with the field gone,
all those extra
, , and interaction terms
have vanished
Can we employ this same technique to explain massive Z and W vector bosons?
These two separate cases will follow naturally by assuming the Higgs field
is aweak isodoublet(with a charged and uncharged state)
withQ = I3+Yw /2and I3 = ±½
Higgs=
+
0
for Q=0Yw = 1
Q=1Yw = 1
couple to EW UY(1) fields: B
0
£
£
Higgs= withQ=I3+Yw /2and I3 = ±½
Yw = 1
Consider just the scalar Higgsrelevant terms
†
†
†
with
Higgs
not a single complex function now, but a vector(an isodoublet)
Once again with each field complex we write
+ = 1 + i2 0= 3 + i4
† 12 + 22 + 32 + 42
†
†
†
Higgs
†
†
†
†
†
†
†
Higgs
†
†
†
†
just like before:
U=½m2† + ¹/4 († )2
2m2
12 + 22 + 32 + 42=
Notice how 12, 22 … 42appear interchangeably in the Lagrangian
invariance to SO(4) rotations
Just like with SO(3) where successive rotations can be performed to align a vector
with any chosen axis,we can rotate within this 1234 space to
a Lagrangian expressed in terms of a SINGLE PHYSICAL FIELD
we’d find EXTRANEOUS unphysical fields with the kind of bizarre interactions
once again suggestion noncontributing “ghost particles” in our expressions.
+
0
Higgs=
So let’s pick ONE field to remain NONZERO.
1or2
3or4
because of the SO(4) symmetry…all are equivalent/identical
might as well make real!
v+H(x)
0
0
v+H(x)
Can either choose
or
But we lose our freedom to choose randomly. We have no choice.
Each represents a different theory with different physics!
v+H(x)
0
0
v+H(x)
or
Aren’t these just orthogonal?
Shouldn’t these just be ZERO?
Yes, of course…for unbroken symmetric ground states.
If nonzero would imply the “empty” vacuum state “OVERLPS with”
or contains (quantum mechanically decomposes into) some of + or 0.
But that’s what happens in spontaneous symmetry breaking:
the vacuum is redefined “picking up” energy from the field
which defines the minimum energy of the system.
v.e.v.!
= v
0
1
This would be disastrous for the choice + = v + H(x)
since0+ = vimplies the vacuum is not chargeless!
But 0 0 = v is an acceptable choice.
If the Higgs mechanism is at work in our world,
this must be nature’s choice.
We’ve worked through 2 MATHEMATICAL MECHANISMS
for manipulating Lagrangains
Introducing SELFINTERACTION terms (generalized “mass” terms)
showed that a specific GROUND STATE of a system need
NOT display the full available symmetry of the Lagrangian
Effectively changing variables by expanding the field about the
GROUND STATE (from which we get the physically meaningful
ENERGY values, anyway) showed
scalar Higgs fields
through a weak isodoublet (with a charged and uncharged state)
+
0
0
v+H(x)
Higgs=
=
which, because of the explicit SO(4) symmetry, the proper
gauge selection can rotate us within the1,2,3,4space,
reducing this to a single observable real field which we
we expand about the vacuum expectation value v.