Problem # 1-6/5

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# Problem # 1-6/5 - PowerPoint PPT Presentation

Problem # 1-6/5. mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm 2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5. Problem #1-6/5. To determine the voltage E coil

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Problem # 1-6/5

mean core length = 52 cm length of air gap = 0.14 cm

cross-sectional area = 18 cm2 air gap flux density = 1.2 T

Determine the voltage E.

Use magnetization curve shown in Fig. 1.5

Problem #1-6/5
• To determine the voltage Ecoil
• Find the current in the coil, Icoil
• Ecoil=IcoilRcoil
• To determine the current Icoil
• Calculate the total mmf
• Calculate the coil current
Problem #1-6/5 continued
• To determine F, calculate H
Problem #1-6/5 continued
• To determine Hcore use Fig. 1.15
• Hcore={1.15 oersteds}{79.577 A-t/m/oersted}
• Hcore=91.5 A-t/m
• Then calculate Fcore
• Fcore=Hcorelcore
• Fcore={91.5 A-t/m}{0.52 m}
• Fcore=47.58 A-t
Problem #1-6/5 continued
• To determine Hgap
• Hgap={1.2 Wb/m2}/{4πx10-7 Wb/A-t-m}
• Hgap=955.4x103 A-t/m
Problem #1-6/5 continued
• Calculating Fgap
• Fgap=Hgaplgap
• Fgap={955x103 A-t/m}{0.0014 m}
• Fgap=1337 A-t
• The total mmf
• Ftotal=Fcore+Fgap
• Ftotal={47.58+1337} A-t = 1384.58 A-t
Problem #1-6/5 continued
• Calculate the coil current Icoil
• Finally, the voltage