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Chapter 19

Chapter 19. Gas Stoichiometry. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP?. 2KBr + Cl 2 → Br 2 + 2KCl.

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Chapter 19

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  1. Chapter 19 Gas Stoichiometry

  2. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl

  3. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr

  4. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 119g KBr

  5. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 119g KBr 2 mol KBr

  6. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 119g KBr 2 mol KBr 1 mol Br2

  7. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3

  8. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3 = 1880 cm3

  9. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3

  10. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2

  11. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 22.4 dm3

  12. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 22.4 dm3 3 mol O2

  13. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g 22.4 dm3 3 mol O2 mol Al

  14. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g = 8.04 g 22.4 dm3 3 mol O2 mol Al

  15. How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl

  16. How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl • This is a volume – volume calculation. • We can use a shortcut for these type of calculations. 50.0 cm3 HCl

  17. How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl • This is a volume – volume calculation. • We can use a shortcut for these type of calculations. 1 cm3 Cl2 50.0 cm3 HCl = 25.0 cm3 2 cm3 HCl

  18. Homework • Gas Laws Lab (due today). • Worksheet: Ideal Gas Equation (due tomorrow). • Worksheet: Gas Stoichiometry (due in two days). • Lab Summary: “Molecular Mass of a Gas” (due in two days). • Study Guide Chapter 19 (due in two days).

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