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6-3 Proving That a Quadrilateral is a Parallelogram.

6-3 Proving That a Quadrilateral is a Parallelogram. *I CAN use the properties of parallelograms to prove that a quadrilateral is a parallelogram. NP. NP. P. P. NP. P. (y + 10) + (3y – 2) = 180. y + 10 = 4x + 13. 4y + 8 = 180. 43 + 10 = 4x + 13. 4y = 172. 40 = 4x. y = 43. 10 = x.

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6-3 Proving That a Quadrilateral is a Parallelogram.

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  1. 6-3 Proving That a Quadrilateral is a Parallelogram. *I CAN use the properties of parallelograms to prove that a quadrilateral is a parallelogram.

  2. NP NP P P NP P

  3. (y + 10) + (3y – 2) = 180 y + 10 = 4x + 13 4y + 8 = 180 43 + 10 = 4x + 13 4y = 172 40 = 4x y = 43 10 = x (4x + 13) + (12x + 7) = 180 10 43

  4. No, an angle of DEFG is not supplementary to both of its consectuive angles, so Thm. 6-9 doesn’t apply

  5. 0 90 90 6ft. The max height occurs when the angles are 90° and PQRS is a rectangle.

  6. Objective Practices • Lesson Check: pg. 372 #1 – 6 • Before you leave class • HW: pg. 372 – 373 #7 – 25 odds

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