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Group IV

Group IV. The Ammonium Carbonate Group Ca 2+ , Sr 2+ , Ba 2+. 目的 學習 第四族 陽離子的分離與確定,精練操作技術與原理應用。. 原理 第四族是在 (NH 4 ) 2 CO 3 與 NH 3 -NH 4 Cl 的緩衝溶液中形成沉澱物以便與其他陽離子分離 BaSO 4 非常的不溶,溶解度為 1.1×10 -10 。 CaSO 4 少溶,溶解度為 2.4×10 -5 。 SrSO 4 少溶,溶解度為 3.2×10 -7 。. Note

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Group IV

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  1. Group IV The Ammonium Carbonate Group Ca2+, Sr2+, Ba2+

  2. 目的 學習第四族陽離子的分離與確定,精練操作技術與原理應用。 原理 第四族是在 (NH4)2CO3與 NH3-NH4Cl 的緩衝溶液中形成沉澱物以便與其他陽離子分離 BaSO4非常的不溶,溶解度為1.1×10-10。CaSO4少溶,溶解度為2.4×10-5。SrSO4少溶,溶解度為3.2×10-7。 Note (1) Ba2+ + CrO42-會形成BaCrO4黃色沉澱,可以證明Ba2+的存在。 (2) CaC2O4是弱酸的鹽類,可以溶於強酸中,因此要形成CaC2O4沉澱必須在鹼性條件下。 (3) Na2CO3當日現配。

  3. + 1d6 M NH4Cl + 15 M NH3鹼化 + 5d(NH4)2CO3 Ba2+ + CO32-→ BaCO3(s) Ca2+ + CO32-→ CaCO3(s) Sr2+ + CO32-→ SrCO3(s) Group IV: 各3滴 Ca2+, Sr2+, Ba2+, 7滴 NH4+ * 加熱太久(NH4)2CO3會分解藥劑量會不足 Stir & ∆ Warm water (<1 min) sol 6-1 Check base + 1d(NH4)2CO3 ppt transfer to ppt 6-1 +HCl酸化 ppt 6-1 + 1~2d 6 M HOAc + 1~3d 3 M NH4C2H3O2 + 10dH2O + 1~3d K2CrO4 * Ba2+ + CrO42-→ BaCrO4(s) 補充CO32-,此溶液儲存太久會將玻璃溶出SiO2降低CO32-濃度 Ca2+ + CO32-→ CaCO3(s) Sr2+ + CO32-→ SrCO3(s) Group V sol 6-2 + 6 M NaOH 鹼化 + 5 drop Fresh Na2CO3 ppt 6-2 + 1~2 d 6 M HCl + 1 mL H2O + ¼ 刮勺 HNH2SO3 ∆Hot water (10 min) * 離心後溶液重複此動作直到無沉澱產生,沉澱的碳酸鹽要用水沖已兩次以移除多餘的 CrO42- * ∆ → ppt 為了分離 Sr(NO3)2,硝酸濃度不可低於16M ppt 6-3 + 2~4d HNO3坩鍋 ∆ 冷卻久一點 +5d16 M HNO3 ×2 (乾玻棒刮內壁,移到乾離心管中) 放在冷水中5 min * * BaSO4(s) (white) Sr2+ + 2NO3-→ Sr(NO3)2(s) 2BaCrO4 + H+→ 2Ba2+ + CrO42- + OH- Ba2+ + SO42-→ BaSO4(s) ppt 6-4 + 5~10d H2O + NH3鹼化 + 三乙醇胺 +(NH4)SO4 sol 6-4 + 1 mL H2O + 15M NH3 鹼化 + (NH4)2C2O4 Ca2+ + C2O42-→ CaC2O4(s) SrSO4(s) white CaC2O4(s) (white) Sr2+ + SO4-→ SrSO4(s)

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