Motion Equations

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# Motion Equations - PowerPoint PPT Presentation

Motion Equations. Mr. King’s Science Class. WORK. WORK = FORCE X DISTANCE. WORK. WORK = FORCE X DISTANCE. Feet or cm. WORK. WORK = FORCE X DISTANCE. Feet or cm. Pounds or grams. WORK. WORK = FORCE X DISTANCE. Feet or centimeters. Pounds or grams. Foot pounds or gram centimeters.

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### Motion Equations

Mr. King’s Science Class

WORK

WORK = FORCE X DISTANCE

WORK

WORK = FORCE X DISTANCE

Feet or cm

WORK

WORK = FORCE X DISTANCE

Feet or cm

Pounds or grams

WORK

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

10 cm

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

10 cm

X

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

20 g

10 cm

X

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

=

20 g

10 cm

X

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

=

20 g

10 cm

200 joules

X

WORK = FORCE X DISTANCE

Feet or centimeters

Pounds or grams

Foot pounds or gram centimeters

WORK

Let’s try a word problem!

Johneal pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board. The spring scale read 80

grams as she pulled it evenly 25 centimeters. How much

work did Johneal do?

WORK

Let’s try a word problem!

Johneal pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board. The spring scale read 80

grams as she pulled it evenly 25 centimeters. How much

work did Johneal do?

WORK = FORCE X DISTANCE

WORK

Let’s try a word problem!

Johneal pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board. The spring scale read 80

grams as she pulled it evenly 25 centimeters. How much

work did Johneal do?

WORK = FORCE X DISTANCE

? = 80g X 25cm

WORK

Let’s try a word problem!

Johneal pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board. The spring scale read 80

grams as she pulled it evenly 25 centimeters. How much

work did Johneal do?

WORK = FORCE X DISTANCE

? = 80g X 25cm

? = 2,000 joule

POWER

Power

POWER

Power =

POWER

Work

Power =

POWER

Work

Power =

POWER

Work

Power =

Time

POWER

Work

Power =

Time

Watt

POWER

Joules

Work

Power =

Time

Watt

POWER

Joules

Work

Power =

Time

Watt

Seconds

POWER

Joules

Work

Power =

Time

Watt

Seconds

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as she pulled it evenly 25 centimeters. How

Much work did Trevor do?

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

= 80 grams x 25 cm

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

= 80 grams x 25 cm

= 2000 joules

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

= 80 grams x 25 cm

WORK

= 2000 joules

POWER =

TIME

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

= 80 grams x 25 cm

WORK

= 2000 joules

POWER =

TIME

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

2000 joules

= 80 grams x 25 cm

WORK

= 2000 joules

POWER =

TIME

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

2000 joules

= 80 grams x 25 cm

WORK

= 2000 joules

POWER =

TIME

5 seconds

Now, let’s try a problem!

Trevor pulled a 100 gram weight using a spring scale up

the smooth side of a chalk board in 5 s. The spring scale

read 80 grams as he pulled it evenly 25 centimeters. How

Much work did Trevor do?

WORK = FORCE X DISTANCE

2000 joules

= 80 grams x 25 cm

WORK

= 2000 joules

POWER =

TIME

400 watts

5 seconds

Velocity

VELOCITY

Velocity

VELOCITY =

Velocity

DISTANCE

VELOCITY =

Velocity

DISTANCE

VELOCITY =

Velocity

Miles or meters

DISTANCE

VELOCITY =

TIME

Velocity

Miles or meters

DISTANCE

VELOCITY =

TIME

Seconds or hours

Velocity

Miles or meters

DISTANCE

VELOCITY =

TIME

Seconds or hours

Miles per hour

Meter per second

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

VELOCTIY

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

VELOCTIY =

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

DISTANCE

VELOCTIY =

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

DISTANCE

VELOCTIY =

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

DISTANCE

VELOCTIY =

TIME

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

600 meters

DISTANCE

VELOCTIY =

TIME

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

600 meters

DISTANCE

VELOCTIY =

TIME

50 seconds

Let’s now try a problem!

Ryan ran 600 meter in 50 seconds, what is his

Velocity?

600 meters

DISTANCE

VELOCTIY =

TIME

12 meters/second

50 seconds

ACCELERATION

ACCELERATION

ACCELERATION

ACCELERATION =

ACCELERATION

VELOCITY

ENDING

ACCELERATION =

ACCELERATION

VELOCITY

ENDING

ACCELERATION =

ACCELERATION

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

ACCELERATION

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

ACCELERATION

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

ACCELERATION

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

ACCELERATION

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

ACCELERATION

Meters/second

Miles/hour

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

ACCELERATION

Meters/second

Miles/hour

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

Seconds/hours

ACCELERATION

Meters/second

Miles/hour

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

Seconds/hours

ACCELERATION

Meters/second

Miles/hour

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

Seconds/hours

ACCELERATION

Meters/second

Miles/hour

Meters/second

Miles/hour

VELOCITY

STARTING

VELOCITY

ENDING

ACCELERATION =

TIME

Meters/second/second

Miles/hour/hour

Seconds/hours

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

3 m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

8 seconds

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s = 4m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

8 seconds

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s = 4m/s

VELOCITY VELOCITY

END START

ACCELERATION =

TIME

8 seconds

4 / 8 = 1/2 meters/sec/sec

OK - Let’s try an acceleration problem

Brandon is traveling in his bike at 3 m/s. He then speeds up

Going down hill and at the bottom of the hill he is traveling

7 m/s. 8 seconds was the time he took to bike down the hill.

What is his acceleration rate?

7 m/s

3 m/s = 4m/s

VELOCITY VELOCITY

END START

ACCELERATION =

1/2 or .5 m/s/s

TIME

8 seconds

4 / 8 = 1/2 meters/sec/sec