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WATERFALL

WATERFALL. BY: MISAKI A., TERESA C., EMILY L., SELINA M. INFO. Length of the ride: 1.2 KM Time of ride: 1.42 min Height of drop: 12.19 m. PART A. What is the velocity of the log before it it ’ s the water?. PART B .

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WATERFALL

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  1. WATERFALL BY: MISAKI A., TERESA C., EMILY L., SELINA M.

  2. INFO Length of the ride: 1.2 KM Time of ride: 1.42 min Height of drop: 12.19 m

  3. PART A What is the velocity of the log before it it’s the water?

  4. PART B What is the deceleration after the log ride hits the water? (it takes 4.5m to slow down to 3m/s)

  5. PART C What is the force of the water? (m-212kg)

  6. PART D 1 Find the average velocity of the ride. (m/s)

  7. PART D 2 Find the average speed of the ride. (m/s)

  8. ANSWER A PE1+KE1=PE2+KE2 mg(12.19)=1/2mv2 12.19(9.8)=1/2v2 238.924=v2 15.5m/s=v Velocity is 15.5 m/s

  9. ANSWER B V2=v2+2ad (3.0)2=(15.5)2+2a(4.5) 9=240.25+9a a=-25.694m/s2 a=-26m/s2

  10. ANSWER C F=ma F=(212)(25.694) F=5447.2 N Fwater= 545oN

  11. ANSWER D1 V=d/t d = 0 because it starts and finish at the same point T=1.42 min -> 201 s V=0/201 Average velocity = 0m/s

  12. ANSWER Q D2 V=d/t d= 1.2km -> 12.00m T= 1.42min -> 201s V=1200/201 Average speed = 6.0 m/s

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