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## ELECTRICAL INSTALLATION PLANNING

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**ELECTRICAL INSTALLATION PLANNING**LSEGG307A 9080F**Lesson Content**• Describe the acceptable methods for determining the maximum demand on an installation’s consumer’s mains. • Calculate the maximum demand for the consumer's mains for given installations up to 400 A per phase.**MD**What is Maximum Demand? Is the “Maximum continuous current that flows in a circuit for a period of 15 minutes or longer” AS/NZS 3000 1.6.3 Why not just put a cable size in, that will handle the current rating for the maximum current rating of the appliance?**What is Maximum Demand?**Domestic stove rated at 5kW Max current = 22A Min cable size = 6mm2 By calculation AS/NZS 3000 Table C4 Max current = 16A Min cable size = 2.5mm2**MD can be determined by:**Calculation Assessment Measurement Limitation AS/NZS 3000 2.2.2. “If the measured current is larger than any of the listed methods, then the MD is considered the measured value”**MD of Mains & Submains**“… may be the ….sum of the current settings of the circuit breakers protecting the associated final sub-circuits….” AS/NZS 3000 Clause 2.2.2 (d)**MD of Mains & Submains**10+10+16+16+32 = By Calculation 16mm2 84 Amps 36 Amps MD = ? Most supply authorities specify a minimum mains cable size of 16 mm2 2.5mm2 10mm2 20 metres 46 metres 10A L1 10A L2 16A P1 16A P2 32A Stove Domestic House**So how do we calculate MD?**Table C1 Table C2 Table C3 • Domestic • Non-domestic • Non- domestic Energy Demand**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii Batten holder = 1 light point 25 lighting points = 1 -20 = 3 A 21 -25 = 2 A 5 A Single House**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii Chandelier or Multi-globe fitting = Number of points = Number of globes = 3 points Single House**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii Power points above 2.3 m for lighting = 1 point Note “e” Exhaust fans below 150W = 1 point Single House**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii Track lights = Every metre = 2 points Note “d” 2 x 2.6 metres track light = 5 points per track = 10 points Single House**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii IXL Tastics, Heat lamps etc Not regarded as “Lighting” Fixed Space Heating Load Group “D” Single House**So how do we calculate MD?**Table C1 Column 2 Lighting Load groups Ai & Aii Outside Lighting Floodlighting, Swimming Pool, Tennis courts, etc Not lighting around house walls If total bigger than 1000W If less than 1000W Load Group “Aii” Single House Load Group “Ai”**Calculations**A house consists of the following: Assume to be <150W 36 light fittings, 3 consisting of 3 lamp combinations 3 bathroom exhaust fans 2 x 750W heat lamp, fan, light combinations 3 x 2metre track lights 12 wall lights around the veranda 6 x 100W bollard lights on driveway 6 x 400W metal halide flood lights for pool Ai Ai D Ai Ai Aii Aii 33 + (3 x 3) = 42P 3P - 3 x 2 x 2 = 12P 12P 13.04A 6 x 100 = 600 3000 W 6 x 400 = 2400 230V Determine the lighting load in Amps**Calculations**A house consists of the following: 36 light fittings, 3 consisting of 3 lamp combinations 3 bathroom exhaust fans 2 x 750W heat lamp, fan, light combinations 3 x 2metre track lights 12 wall lights around the veranda 6 x 100W bollard lights on driveway 6 x 400W metal halide flood lights for pool Ai Ai D Ai Ai Aii Aii 33 + (3 x 3) = 42P 3P - 3 x 2 x 2 = 12P 12P 13.04A 42P 3P 12P 12P 1 – 20 = 21 – 40 = 41 – 60 = 61 – 69 = 3A 2A 2A 2A 22.04A 69P 9A + 13.04A =**3 Light Calculations**Broken up evenly ABC 36 light fittings 12 Fittings / 3A 3A 3A 3 Should indicate how it is to be broken up across the three phases NOT ABC 36 light fittings = 3A + 2A = 5A 1.6 1.6 1.6 3**Calculations**A house consists of the following: Broken up evenly over 3 Phases 36 light fittings, 3 consisting of 3 lamp combinations 3 bathroom exhaust fans 2 x 750W heat lamp, fan, light combinations 3 x 2metre track lights 12 wall lights around the veranda 6 x 100W bollard lights on driveway 6 x 400W metal halide flood lights for pool Ai Ai D Ai Ai Aii Aii 11 + (1 x 3) = 14P 1P - 1 x 2 x 2 = 4P 4P 4.35A Divide by 3 14P 1P 4P 4P 1 – 20 = 21 – 23 = 3A 2A 9.35A / 23P 5A + 4.35A =**Power Points**Notes h Double Power Points Load Group Bi 36 Double Power Points 6 Single power points 36 x 2 =72P 6P 1 – 20 = 21 – 40= 41 – 60 = 61 – 78 = 10A 5A 5A 5A 78P 25A**Power Points**Notes h Double Power Points Load Group Bi 36 Double Power Points 6 Single power points 36 x 2 =72P 6P 1 – 20 = 21 – 40= 41 – 60 = 61 – 78 = 10A 5A 5A 5A AND 78P Other Direct Wired Equipment that is <10A 25A • Air conditioners • Cook tops • Water heaters**Power Points**NOT 15 A Power Points Other Equipment that is Covered in Load Groups below Load Group Bii C Ranges, Laundry equipment D Fixed Space Heating or cooling equipment E & F Water Heaters G Spa & Swimming Pool Heaters 15 A Power Points suppling this equipment is covered under each load group**Calculations**A house consists of the following: 20 Double power points 8 Single power points 8A swimming pool pump 4 x 15A power points 12A Air-conditioner supplied via a 15A power point 14A Pool heater direct wired Bi Bi Bi Bii D G 20 x 2 = 40P 8P 1P 10A - - 3 Determine the Power point load in Amps**Calculations**A house consists of the following: 20 Double power points 8 Single power points 8A swimming pool pump 3 x 15A power points 12A Air-conditioner supplied via a 15A power point 14A Pool heater direct wired Bi Bi Bi Bii D G 20 x 2 = 40P 8P 1P 10A - - 40P 8P 1P 1 – 20 = 21 – 40 = 41 – 49 = 10A 5A 5A 30A 49P 20A + 10A =**Load Group C**• Cook tops • Wall ovens • Washing machines • Clothes driers Must be over 10A If supplied via a power point That power point is NOT included in Bi, Bii or Biii 50% of connected Load An installation has: 2.3 kW Cook top 4 kW Wall oven 6.3 kW of Load Group C (6300/230) x 0.5 = 13.7A**Load Group D**• IXL Tastics Heat lamps • Air conditioners • Heaters • Under floor heating Must be over 10A If supplied via a power point That power point is NOT included in Bi, Bii or Biii 75% of connected Load If reverse cycle Air-conditioner is used only the highest system is to be taken into account Unless it is multi zone, when both heating and cooling could operate simultaneously**Load Group E &F**Water Heaters Load Group E 15 litre heater with a 2.4kW element 33.3% of connected load 2400/15 = 160 W/L • Instantaneous • Quick recovery If greater than 100W/L Load Group F 300 litre heater with a 2.4kW element 100% of connected load • Storage • Off peak 2400/300 = 8 W/L**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 43P 3 + 2 + 2 = 7A**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 7A 44 + 4 = 48P 10 + 5 + 5 = 20A 44P**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 7A 20A (10000/230) x 0.5 = 21.7A**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 7A 20A 21.7A 9.75A 13 x 0.75 =**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 7A 20A 21.7A 9.75A 4600/230 = 20A**Maximum Demand**A house consists of the following: Ai Ai Bi Bi C D F 41 x 50 W down lights 2 x 60 W exhaust fans 4 x Single 10 A socket outlets 22 x Double 10 A socket outlets 1 x 10kW range 1 x Permanently connected air conditioner (full load current of 13 A) 1 x 4.6 kW continuous HWS 7A 20A 21.7A 9.75A 20A 78.45A**Uneven 3Loads**Not all single phase loads will break up evenly over three phases But the phases must not be unbalanced by more than 25A NSW S&IR Clause 1.10.3**3Maximum Demand**A house consists of the following: Ai Ai • Aii Bi Bi • Bii C C F D A • B • C • A • B • C • A • B • C • A • B • C 30 x Light points + 2 x Exhaust fans 18 x Lights 6 x 400W mercury vapour flood lights 15 x Double power points (p/p) • 10 x Single p/p & 15 x Double p/p 3 x 15ASingle p/p 1 x 4.1kW wall oven 1 x 4.6kW cook top • 1 x 3.6kW heat pump HWS • 1 x 5.7kW 3 Air conditioner**3Maximum Demand**A house consists of the following: Ai Ai • Aii Bi Bi • Bii C C F D A • B • C • A • B • C • A • B • C • A • B • C 30 x Light points + 2 x Exhaust fans 18 x Lights 6 x 400W mercury vapour flood lights 15 x Double power points (p/p) • 10 x Single p/p & 15 x Double p/p 3 x 15ASingle p/p 1 x 4.1kW wall oven 1 x 4.6kW cook top • 1 x 3.6kW heat pump HWS • 1 x 5.7kW 3 Air conditioner 32P 3+2A = 5A 15A 8.91A 6.17A 3A 20A 10A 6.17A 18P 7.83A 10A 15.65A 6.17A ((6x400)230)x0.75= 30P 10+5A = 10+30P 10+5A = (4100230)x0.5= (4600230)x0.5= 3600230= (5700x0.75)(√3 x400)= 35.1A 39.2A 40.2A**Multiple Domestic**Unit 1 MSB Unit 2 Unit 3 Columns 3, 4 or 5 Column 2 Submains to individual units**Questions to be Asked?**• How many units are there? • How are they spread across the 3 phases? 6 Units = 2 Units / Phase Use Colum 3 3 18 Units = 6 Units / Phase Use Colum 4 3 66 Units = 22 Units / Phase Use Colum 5 3**Maximum Demand**A house consists of the following: Ai Ai • Aii Bi Bi • Bii C D F 26 x Light points 2 metres of light track 2 x 750W flood lights 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 26 + 4 = 30P 3A + 2A = 5A 4.9A 20A 10A 12.2A 11.7A 10.4A 2 x 2 = 4P 1500W (1500W/230V)x0.75 10A + 5A + 5A = 26 x 2 = 52P 52 + 5 = 57P (5600W/230V)x0.5 (3600W/230V)x0.75 (2400W/230V) 74.2A**Multiple Domestic**9 Units consists of the following: 9 Units = 3 Units / Phase Use Colum 3 3 Ai Ai • Aii Bi Bi • Bii C D F 26 x Light points 2 metres of light track 2 x 750W flood lights 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 6A 25A 10A 15A 35.2A 18A Not counted 10A + (5A x 3) = (3600W/230V) x 0.75 x 3 6A x 3 = 109A**Multiple Domestic**30 Units consists of the following: 30 Units = 10 Units / Phase Use Colum 4 3 Ai Ai • Aii Bi Bi • Bii C D F 26 x Light points 2 metres of light track 2 x 750W flood lights 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 7.5A 52.5A 10A 28A 117A 60A 5A + (0.25A x 10) = Not counted 15A + (3.75A x 10) = 2.8A x 10 = (3600W/230V) x 0.75 x 10 6A x 10 = 275A**Multiple Domestic**66 Units consists of the following: 66 Units = 22 Units / Phase Use Colum 5 3 Ai Ai • Aii Bi Bi • Bii C D F 26 x Light points 2 metres of light track 2 x 750W flood lights 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 11A 91.8A 10A 61.6A 258A 118A 0.5A x 22 = Not counted 50A + (1.9A x 22) = 2.8A x 22 = (3600W/230V) x 0.75 x 22 100A + (0.8A x 22) = 550A**What Happens If The Number Of Units Is Not Devisable By 3?**16 Units = 5.33 Units / Phase 3 A B C 5 Units 5 Units 6 Units Col 3 Col 3 Col 4 But the phases must not be unbalanced by more than 25A NSW S&IR Clause 1.10.3**Multiple Domestic**16 Units consists of the following: 5Units / A & B Use Colum 3 Ai Bi Bi • Bii C D F 26 x Light points 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 6A 35A 10A 15A 58.7A 52.2A 10A + (5A x 5) = (3600W/230V) x 0.75 x 5 (2400230V) x 5 = 176.9A**Multiple Domestic**16 Units consists of the following: 6Units / C Use Colum 4 Ai Bi Bi • Bii C D F 26 x Light points 26 x Double 10 A socket outlets • 5 x Single 10 A socket outlets 1 x 15ASingle socket outlet 1 x 5.6kW wall oven / cook top 1 x 3.6kW air conditioner 1 x 2.4kW storage HWS (Heat pump) 5A + (0.25A x 6) = 6.5A 37.5A 10A 16.8A 70.4A 36A 15A + (3.75A x 6) = 2.8A x 6= (3600230) x 0.75 x 6 6A x 6 = 177.2A**What Happens If The Number Of Units Is Not Devisable By 3?**16 Units = 5.33 Units / Phase 3 A B C 5 Units 5 Units 6 Units Col 3 Col 3 Col 4 176.6A 176.6A 177.2A**Communal Load**• Driveway/ parking lighting • Stairwell lighting • Power points for cleaners • Lifts • Swimming pool pumps Loads that are used by all the unit dwellers**Multiple Domestic**16 Units have a communal load consists of the following: H H I • Ji Jii D E 20 x 80 W bollard Lights 30 x light points • 15 x Single 10 A socket outlets 1 x 3.6kW HWS for cleaners room 1 x 3.6kW Air conditioner for lobby 1 x 12A pool pump/filter 1 x 15A lift motor ((20x80)230) + ((30x 60)230)= 14.78A 15A 7.8A 15A 12A 18.75A 2A x15= 30 but maximum of 15A (3600230) x 0.5 = (3600230) x 0.75 = 15 x 1.25 = Table C2 Colum 2 83.33A These circuits could also be divided across three phases**Socket outlets**In a Factory On each Phase 1000W + 19 x 750W = 15.25kW 15250 ÷ 230 = 66.3 Amps In areas with air conditioning • 20 x 10A single power points 1000W + 19 x 100W = 2.9kW 2900 ÷ 230 = 12.6 Amps • 20 x 10A single power points**Socket outlets**• 5 x 10A 3 outlets Treat as B(i) 1000W + 4 x 750W = 4kW Per Phase 17.4 Amps 4000 ÷ 230 = • 2 x 32A 3 outlets • 5 x 20A 3 outlets Per Phase 75% x 32A 75% x 20A x 5 131Amps 32A + 24A + 75A =