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Gas Law Properties Analysis: Pressure, Temperature, and Volume

Utilize pressure (P), temperature (T), or volume (V) measurements to identify gas properties. Learn to convert units and solve gas law equations with steps illustrated.

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Gas Law Properties Analysis: Pressure, Temperature, and Volume

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  1. DO NOW:Use P (pressure), T (temperature) or V (volume) to tell which property of a gas is described in each of the following measurements:7. ______________________ 730 torr8. ______________________ 2 atm9. ______________________ 320 K10. ______________________ 87 ml11. ______________________ absolute zero12. ______________________ 492 liters13. ______________________ 2.4 ml

  2. Combine gas law • STP = standard temperature and pressure • ST = standard temp = 273K • SP = standard pressure = 1 atmor 101.3 kPa

  3. Step 1 • if temperature is not in K, convert! • K = C + 273 • C = K - 273

  4. Step 2: Plug the numbers into the equation PV PV T T =

  5. Step 3: Solve 80 ml x 96 kPa V x 99 kPa 300 K 273K = 80 x 96 x 273 = V x 99 x 300 80 x 96 x 273 = V (99 x 300)

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