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Ideal Gas Law & Gas Stoichiometry

Ideal Gas Law & Gas Stoichiometry. Ideal Gas Law. P V = n R T P = Pressure (atm) V = Volume (L) T = Temperature (K) n = number of moles R = 0.0821 L atm / mol K. PV = nRT. Calculate the number of moles of a gas contained in a 3.0 L vessel at 300.0K with a pressure of 1.50 atm. Example.

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Ideal Gas Law & Gas Stoichiometry

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  1. Ideal Gas Law & Gas Stoichiometry

  2. Ideal Gas Law P V = n R T • P = Pressure (atm) • V = Volume (L) • T = Temperature (K) • n = number of moles • R = 0.0821 L atm / mol K

  3. PV = nRT • Calculate the number of moles of a gas contained in a 3.0 L vessel at 300.0K with a pressure of 1.50 atm

  4. Example Dinitrogen monoxide (N2O), laughing gas, is used by dentists as an anesthetic. If 2.86 mol of gas occupies a 20.0 L tank at 23°C, what is the pressure (mmHg) in the tank in the dentist office? Note: 1atm = 760 mm Hg

  5. Permutations of the Ideal Gas Law PV = mRT M • P = Pressure (atm) • V = volume (L) • m = mass of the gas (g) • R = 0.0821 L atm / mol K • T = Temperature (K) • M = molecular mass

  6. Example • What is the pressure 2.0 g of nitrogen gas in a 5.0 L container at 300.0 K?

  7. Permutations of the Ideal Gas Law P = DRT M • P = pressure (atm) • D = density (g/L) • R = 0.0821 L atm / mol K • T = temperature (K) • M = molecular mass

  8. Example • What is the molar mass of a gas that has a density of 1.40 g/L at STP? • NOTE – STP is standard temperature and pressure • At STP temperature is 273 K and pressure is 1.00 atm

  9. Avogadro’s Principle • _________________– equal volumes of gases at equal temperature and pressure contain the same number of particles • ________________– the volume of gas that 1 mole of a substance occupies at STP • At STP 1 mol of a gas = ____________ • New conversion factor at STP ONLY! 1 mol 22.4 L

  10. Example • Calculate the volume 0.881 mol of a gas will occupy at STP.

  11. Example • Calculate the volume that 2.000 kg of methane would occupy at STP.

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