Algebraic Solving Method. Balancing Chemical Equations. Balance This Equation. Pb(N3)2 + Cr(MnO4)2 ïƒ Cr2O3+ MnO2 + Pb3O4 + NO. Pb(N 3 ) 2 + Cr(MnO 4 ) 2 ïƒ Cr 2 O 3 + MnO 2 + Pb 3 O 4 + NO Let Pb(N 3 ) 2 = A Let Cr(MnO 4 ) 2 = B Let Cr 2 O 3 = C Let MnO 2 = D Let Pb 3 O 4 = E
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Balancing Chemical Equations
Pb(N3)2 + Cr(MnO4)2 Cr2O3+ MnO2 + Pb3O4 + NO
Let Pb(N3)2 = A
Let Cr(MnO4)2 = B
Let Cr2O3= C
Let MnO2= D
Let Pb3O4= E
Let NO= F
Give Each Compound a Variable
* A is the amount of Pb on the left side of the equation
*3E is the amount on the left side
Find a lowest common multiple of 2 and 3
Multiply each side by 6
Substitute each value into the equation.
15Pb(N3)2 +44 Cr(MnO4)2 22Cr2O3+ 88MnO2 + 5Pb3O4 +90 NO
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