Essential Questions

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## Essential Questions

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**Essential Questions**• Go to the heart of a discipline • Recur naturally throughout one’s learning and in the history of a field • Raise other important questions**Essential Questions Examples**• Must a story have a moral, heroes, and villains? • How does an organism’s structure enable it to survive in its environment? • Who is a friend? • Do we always mean what we say and say what we mean?**More Essential Questions**• What makes a video game “good”? • Where do Waves Come From? • When is Fighting Good and When Is it Bad? • What is a Home? • Who Owns the Internet?**Unit Questions**• Provide subject- and topic- specific doorways to essential questions • Have no obvious “right” answer • Are deliberately framed to provoke and sustain student interest**Unit Questions Examples**• Is Huck Finn a hero? • Has history proven that the enemy of my enemy is my friend? • How do cats see in the dark? • Does technology always lead to progress? • Is the gap between rich and poor better now than 100 years ago?**Essential Question**Are vacations worth the cost?**Unit Questions**• What is the greatest expense of traveling abroad? • Which country would be the most interesting to visit? • What is the best travel method for seeing a country? • How would you estimate the cost of traveling in Germany?**Unit Question**Are Germany’s gas prices affordable?**Joe’s Trip to Germany**By Richard Holden**Statement of Problem**• Joe is planning a trip to Germany • He will rent a car to drive while there • He knows the places he plans to go • He wants to know how much he will spend on gas while there (in U.S. dollars)**Joe Quantifies the Information**• Know the total distance to drive • Know the price of gasoline in Germany • Know how many miles/gallon he gets • Know the conversions: • For kilometers to miles • For gallons to liters • For Deutsch Marks to dollars**Total Distance to Drive**Joe studies a map of Germany and finds he will drive a total of 6500 kilometers.**Price of Gas in Germany**• Joe finds out from an Internet search that the price of gasoline in Germany is 1.6 DM per liter (they are still accepting Deutsche Marks in Germany)**Miles Per Gallon**Joe’s car gets 32 miles per gallon**Conversions**• 1 Km = 0.62 miles • 1 gal = 3.785 liters • 1.99 DM = $1.00**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known**The Secret!!!**• Use ratios equal to one (identity property of multiplication) • Set up each ratio so units will cross cancel • Begin with the distance (6500 km) • Continue until the distance is changed to dollars**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km Next: Find an equation with Km in it**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km X 0.62 mi 1 Km Next: Find an equation with miles in it**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km X 0.62 mi X 1 gal 1 Km 22 mi Next: Find an equation with gallons in it**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km X 0.62 mi X 1 gal X 3.785 liters 1 Km 22 mi 1 gal Next: Find an equation with liters in it**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km X 0.62 mi X 1 gal X 3.785 liters X 1.6 DM 1 Km 22 mi 1 gal 1 liter Next: Find an equation with DM in it**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution 6500 Km X 0.62 mi X 1 gal X 3.785 liters X 1.6 DM X $1.00 1 Km 22 mi 1 gal 1 liter 1.99DM Finally, multiply by the numerators and then divide by the denominators.**Distance is 6500 Km**Gas price is 1.6 DM/liter Car gets 22 mpg 1 Km = 0.62 miles 1 gal = 3.785 liters 1.99 DM = $1.00 What is Now Known The Solution will be in Dollars 6500 Km X 0.62 mi X 1 gal X 3.785 liters X 1.6 DM X $1.00 1 Km 22 mi 1 gal 1 liter 1.99DM $557.46