More Bacteria Practice

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## More Bacteria Practice

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**More Bacteria Practice**Ecoli**Question #3**• Next = Now *2**Question 4-7**• 4. • 5. r=2 • 6. amount of bacteria after 2 hours • 7. between the 12th and 13th 10-min. interval which is between 120 min to 130 min (2 hr to 2hr and10min)**Mold Growth**• The Exponential Equation m= is the area of the mold d= days**Question 8-9**• 8. What is the area of the mold at the start of the experiment? • 50 • 9. What is the growth factor or common ratio? • r=3**Question# 10-11**• What is the area of the mold after 5 days? 12,150 m^2 11. On which day will the area of the mold reach 6,400 m^2 ? Between 6 and 7 days**Question #12**A). What value does b have in the mold equation? 3 What does this value represent? The growth factor. B). What value does a have in the mold equation? 50 What does the value represent? The initial value**Killer Plants Activity**Question #1**Question #3-4**• Next = Now*2 • The y represents the area covered by these killer plants. • The x represents the number of months • 1,000 represents the initial population. • 2 Represents the growth rate**Question #5-6**• How much the Lake surface will be covered in one year (12 months)? 1000*2^11 • 2,048,000 • How many months will the plant completely cover the surface of the lake? • The surface of the lake is 25, 000, 000 • So it would take between the 14th and 15th month to cover the entire lake surface.**Here is the Situation….**• Your spaceship has crashed on an unknown planet. You and your crew encounter a drooling, carnivorous alien monster. As you can guess, this is not good. It gets worse. While you are cowering in a cave, trying not to cry “mommy” in front of your crew, your science officer is able to chart the monster’s growth over several hours’ time. She comes back to you with her report(and minus one arm).**Continued…….**• The news is grim. With each hour that passes, the monster doubles is size (specifically, his height). The science officer also said that the monster’s stomach was making those growly-hungry noises.**Monsters and Amoebas**• The formula to use to describe the growth of the monster is**Silently Read 2-5 minutes**• After filling out the table…. Read the remaining paragraphs at the bottom of the page and then do the Your Turn**Your Turn**• How tall would the monster be 4.7 hours after birth? 2^(4.7)= 25.99 ft • How tall would the monster be 3.2 hours after birth? 2^(3.2)= 9.18 ft**Please Write in your Notes**Exponent is a variable. Base The is called an “exponential function”. There is a variable up in the exponent.**Lets Get Back to the Story…**For some reason, you science officer starts yelling crazy things at you (while waving around her one arm) and quits. In desperation, you promote the crew cook, Stu, and send him out of the cave to do some exploring. Unfortunately, he finds a second species of drooling alien monster. Fortunately for Stu, it’s an herbivore! Unfortunately for Stu, your uniforms are green. Days later, one of Stu’s sock and clip board of growth data for the monster is found.**Here is what Stu wrote……**• SECOND ALIE SPECIES IS 4 INCHES TALL AT BIRTH. • CONCLUSIONS: WITH EACH HOUR THAT PASSES, THE MONSTER TRIPLES IN HEIGHT AND MAY BE TASTY BROILED WITH ONIONS. • FORMULA FOR GROWTH: 4*3^T**Your Turn Again**• Complete the Your Turn activity….. With your group. • ( Work with a purpose!)**Your Turn Part 2**• How tall will this species of monster be after 2.5 hours? • 4* 3^2.5 = 62.35 • How tall will it be after 4.2 hours? • 4*3^4.2 = 403.6**Back to the Story…**You are sent out of the cave next. You find a third species of alien monster. It is not drooling, but is does have a serious breath problem. You find that the species is 2 cm tall at birth and gets five times as tall with each day that passes.**3rd Monster**• Formula: • How tall will the monster be after 3.7 days • Y = 2* 5^3.7 = 771.29**And the story continues…**Going from large to small, you find another type of critter on the planet: alien amoebas! Since you’re stranded on the planet and there’s nothing else to do except run screaming from some of the inhabitants, you decide to study amoebas populations.**Continued….**• Typically animal populations grow by mommy and daddy animals making baby animals….. Hey- this lesson is G-rated!) Amoebas populations, on the other hand, grow by each amoeba splitting into two amoebas. So, if each alien amoeba splits into 2 amoebas every hour, can we create a formula to describe the growth of the amoeba population?**Silent Reading Again…**• Read the read of the information on the page and do the Your turn on this page only**Amoebas Splitting changes**• Answer from the silent reading • 37* 1.25^6 = 141.14**Your Turn Again (Amoebas)**• Initial Population : 153 • Growth Factor : 2.4 • Equation: • 153*2.4^7= 70,173.01 • 2nd Problem: • Initial Population: 200 • Split Factor: 1.7 • Number of Splits: 14 • 200*1.7^14 = 336,755.65**Your Turn Again and Again**• Initial Population: 30 • Growth Factor: 1.15 every minute • How many in 1 and ½ hour = 90 minutes • So… • Y = 30* 1.15^90 = 8708169.77