1 / 10

(0,y)

1. A triangle is bounded by the x-axis, y-axis and the line that passes through the point (2,1) with x-intercept at (x,0) and y-intercept at (0,y). Express the area of the triangle as a function of x. (0,y). •. (2,1). •. (x, 0). •. f(x) = area of triangle. (0,y). •. f(x) = b h. (2,1).

Download Presentation

(0,y)

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 1. A triangle is bounded by the x-axis, y-axis and the line that passes through the point (2,1) with x-intercept at (x,0) and y-intercept at (0,y). Express the area of the triangle as a function of x. (0,y) • (2,1) • (x, 0) •

  2. f(x) = area of triangle (0,y) • f(x) = b h (2,1) ? • 2 (x, 0) • ? f(x) = x y 2 y = ? (in terms of x) y • (2, 1) x 1 x – 2

  3. f(x) = area of triangle y f(x) = b h x 2 1 f(x) = x y x – 2 2 x y f(x) = x • x x – 2 = x – 2 1 2 y = x x – 2

  4. x2 f(x) = x - 2 2 1 f(x) = x2 1 • x - 2 2 x2 f(x) = 2x – 4

  5. 2. Two cars are both approaching an intersection. Car A is traveling at 45 mph and is presently 100 miles from the intersection while car B is running at 32 mph and is 150 miles from the intersection. Express the distance between the two cars as a function of time in hours, h.

  6. f(x) = distance car A 45 mph distance 100 m 150 m car B 32 mph

  7. distance 100 150 f(x) = distance distance 100 – 45h 150 – 32h

  8. f(x) = distance f(x) = (100 – 45h)2 + (150 – 32h)2 distance 100 – 45h 150 – 32h

  9. 3. The CEO of a certain company that manufactures calculators noticed that when a calculator was sold at $100 each, a total of 10,000 calculators were sold in a month. He also noticed that for every $5 increase in the price of the calculator, there was a decrease of a 100 pieces of it being bought. Express the revenue of the company as a function of the number of $5 increase in price.

  10. number of units sold price • revenue = revenue = $100 • 10,000 = $1,000,000 revenue = $ 105 • 9,900 = $1,039,500 revenue = $ 110 • 9,800 = $ 1,078,000 x = no. of $ 5 increase revenue = (100 + 5x) (10,000 – 100x)

More Related