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第十单元 酸和碱

第十单元 酸和碱. 一、选择题： 1—5 ADCDB 6—10 BCCCB 11—15 CACAD. 二、简答与填空： 16. 石灰水 Ca(OH) 2 + CO 2 = CaCO 3 ↓+ H 2 O 氢氧化钠 17. 减小 挥发 变黑 炭化 腐蚀 18. （ 1 ）与 CO 2 反应 2NaOH + CO 2 = Na 2 CO 3 + H 2 O 密封 （ 2 ） Na 2 SiO 3 19. ＞ 红 三 5 ： 1 20.A ＞ C ＞ B A. 三、实验与探究：

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第十单元 酸和碱

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  1. 第十单元 酸和碱 一、选择题： 1—5 ADCDB 6—10 BCCCB 11—15 CACAD

  2. 二、简答与填空： 16.石灰水 Ca(OH)2 + CO2 = CaCO3↓+ H2O 氢氧化钠 17.减小 挥发 变黑 炭化 腐蚀 18.（1）与CO2反应 2NaOH + CO2 = Na2CO3 + H2O 密封 （2）Na2SiO3 19.＞ 红 三 5：1 20.A＞C＞B A

  3. 三、实验与探究： • 22. 2NaOH + CO2 = Na2CO3 + H2O • 稀盐酸 气泡产生 氯化钙 • 氢氧化钙 • Ca(OH)2 + Na2CO3= CaCO3↓+ 2NaOH

  4. 23.①取少许废水于试管中，向里边滴加无色酚酞溶液，看是否变红23.①取少许废水于试管中，向里边滴加无色酚酞溶液，看是否变红 • ②解：设可处理废水的质量是x H2SO4的质量是9800kg×20%=1960kg • H2SO4 + 2NaOH = Na2SO4 + 2H2O 98 80 1960kg x 由98/80=1960kg /x得： x=100000Kg 答：可处理废水的质量是100000kg

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