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1-1 Using Trigonometry to Find Lengths. You have been hired to refurbish the Weslyville Tower… (copy the diagram, 10 lines high, the width of your page.). In order to bring enough gear, you need to know the height of the tower……. How would you determine the tower’s height?.

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Presentation Transcript
slide2
You have been hired to refurbish the Weslyville Tower…(copy the diagram, 10 lines high, the width of your page.)

In order to bring enough gear, you need to know the height of the tower……

How would you determine the tower’s height?

slide3
When it is too difficult to obtain the measurements directly, we can operate on a model instead.
  • A model is a larger or smaller version of the original object.
slide4
A model must have similar proportions as the initial object to be useful.
  • Trigonometry uses TRIANGLES for models.

We construct a similar triangle to represent the situation being examined.

imagine the sun casting a shadow on the ground
Imagine the sun casting a shadow on the ground.

Turn this situation into a right angled triangle

the length of the shadow can be measured directly
The length of the shadow can be measured directly

The primary angle can also be measured directly

X

The Height?

Sooo…

40O

200 m

slide7
Make a model!!

Draw a right angled triangle with a base of 20 cm and a primary angle of 40O, then just measure the height!

slide8

X cm

=

20 000 cm

We can generate an equation using equivalent fractions to determine the actual height!

General Model Real

X cm

Height

17 cm

=

=

Base

20 000 cm

20 cm

0.85

20 000 (0.85) = X

170 m = X

in the interest of efficiency
In the interest of efficiency..
  • Drawing triangles every time is too time consuming.
  • Someone has already done it for us, taken all the measurements, and loaded them into your calculator
  • Examine the following diagram
slide10

O

O

O

O

As the angle changes, so

shall all the sides

of the triangle.

Recall the Trig names for different sides of a triangle…

geometry
Geometry

hypotenuse

height

O

base

Trigonometry

hypotenuse

opposite

“theta”

adjacent

slide12
Trig was first studied by Hipparchus (Greek), in 140 BC.

Aryabhata (Hindu) began to study specific ratios.

For the ratio OPP/HYP, the word “Jya” was used

slide13
Brahmagupta, in 628, continued studying the same relationship and“Jya” became “Jiba”

“Jiba became Jaib”which means “fold” in arabic

slide14
European Mathmeticians translated “jaib” into latin:

SINUS

(later compressed to SIN by Edmund gunter in 1624)

slide15
Given a right triangle, the 2 remaining angles must total 90O.

A = 10O, then B = 80O

A = 30O, then B = 60O

A

A “compliments” B

C

B

slide16
The ratio ADJ/HYP compliments the ratio OPP/HYP in the similar mathematical way.

Therefore, ADJ/HYP is called “Complimentary Sinus”

COSINE

the 3 primary trig ratios
The 3 Primary Trig Ratios

SINO = opp

O

hyp

COSO = adj

hyp

hyp

opp

TANO = opp

adj

adj

soh cah toa
soh cah toa

1

A

X 17

FIND A:

17 X

COS25O =

17

1

A = 17 X cos25O

17m

A = 15.4 m

25O

A

soh cah toa1
soh cah toa

1

A

X 12

FIND A:

12 X

SIN32O =

12

1

A = 12 X SIN32O

12 m

A = 6.4 m

A

32O

soh cah toa2
soh cah toa

1

A

X 10

FIND A:

10 X

TAN63O =

10

1

A = 10 X TAN63O

63O

A = 19.6 m

10 m

A

tan 40 o

X

Tan 40O =

200

200 (Tan40O) = X

168 m = X

X

40O

200 m

slide23
Page 8

[1,2] a,c

3-7

find the height of the building

TAN 50 = H

150

1

150 X

X 150

Find the height of the building

1

(150) TAN 50 = H

HYP

OPP

H

150 m

ADJ

50O

ad