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P – obwód = 32 cm a –bok = 32/4 = 8 cm DE = DF = FC = DA = EA = = a/2 = 8 cm/2 = 4 cm PowerPoint Presentation
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P – obwód = 32 cm a –bok = 32/4 = 8 cm DE = DF = FC = DA = EA = = a/2 = 8 cm/2 = 4 cm

P – obwód = 32 cm a –bok = 32/4 = 8 cm DE = DF = FC = DA = EA = = a/2 = 8 cm/2 = 4 cm

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P – obwód = 32 cm a –bok = 32/4 = 8 cm DE = DF = FC = DA = EA = = a/2 = 8 cm/2 = 4 cm

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  1. P – obwód = 32 cm a –bok = 32/4 = 8 cm DE = DF = FC = DA = EA = = a/2 = 8 cm/2 = 4 cm P1 – pole trójkata DFE = DE * DF/2 = = 4 * 4/2 = 16/2 = 8 cm^ P2 – pole trójkata EAB = EA * AB/2 = = 4 * 8 /2 = 32/2 = 16 cm^ P3 – pole trójkata BCF = P2 = 16 cm^ P4 pola wszystkich trójkątów = P1 + P2 + P3 = 8 + 16 + 16 = 40 cm^ P5 – pole kwadratu = 8 * 8 = 64 cm^ P6 – pole trójkata czerwonego = P5 – P4 = = 64 cm^ - 40 cm^ = 24 cm^ D F C E A B