applications of the derivative n.
Skip this Video
Loading SlideShow in 5 Seconds..
Applications of the Derivative PowerPoint Presentation
Download Presentation
Applications of the Derivative

Loading in 2 Seconds...

play fullscreen
1 / 21

Applications of the Derivative - PowerPoint PPT Presentation

  • Uploaded on

Applications of the Derivative. By Michele Bunch, Kimberly Duane and Mark Duane. Extreme Values. Critical values – any value along f(x) where f’(x) = 0 OR f’(x) is undefined These help you determine extreme values: Relative max/min → over ENTIRE FUNCTION

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
Download Presentation

Applications of the Derivative

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
applications of the derivative

Applications of the Derivative

By Michele Bunch, Kimberly Duane and Mark Duane

extreme values
Extreme Values
  • Critical values – any value along f(x) where f’(x) = 0 OR f’(x) is undefined

These help you determine extreme values:

  • Relative max/min → over ENTIRE FUNCTION
  • Absolute max/min → over an INTERVAL
    • If f(x) is continuous on a closed interval, extrema could be at CV’s OR at endpoints – check them all!
  • Key words
    • If it asks WHERE the max/min is, it wants the x value
    • If it asks WHAT it is, then it wants the value

Find the absolute max and min on the interval [-3,2]

Critical Values


Because x=4 is not in the interval, you don’t have to test it IN THIS CASE!!

Absolute max: x=2

Absolute min: x=-3

1 st derivative test
1st Derivative Test

This is a test that uses the first derivative to help you find relative maxes and mins.

1. Find critical values and create a number line of f’(x) with these values.



x = 1 is a local max; x = 4 is a local min

2. Use f’(x) to determine if f’(x) is positive or negative.

-- If f’(x) is positive, f(x) is increasing

-- If f’(x) is negative, f(x) is decreasing

3. If f’(x) changes from positive to negative, the CV is a local max.

If f’(x) changes from negative to positive, the CV is a local min.

2 nd derivative test
2nd Derivative Test

Still a test for determining local max and min!

1. Take the 2nd derivative, set it equal to zero, and solve.


2. Place these values on a number line for f”(x) and use f”(x) to determine if f”(x) is positive or negative.

3. For the critical values:

-- If f”(CV) is positive, then the CV is a local min

-- If f”(CV) is negative, then the CV is a local max


Concave Up

Concave Down

Looks like this:

Looks like this:

  • f’(x) is increasing
  • f”(x) is positive
  • This means the slopes are always increasing
  • f’(x) is decreasing
  • f”(x) is negative
  • This means the slopes are always decreasing
f x f x and f x
f(x), f’(x), and f”(x)
  • The graph of the derivative is essentially the slope of the tangent line as it travels along the curve.
  • For every point on f(x) that has a horizontal tangent line, f’(x) will cross the x axis at that same point.
  • If the slope of the tangent line is positive and increasing for f(x), f’(x) will be positive (and vice versa)
  • f’(x) and f”(x) have the same relationship as f(x) and f”(x)
mean value theorem
Mean Value Theorem

Given a differentiable function over an interval, there is at least one point on the curve where the derivative is equal to the average derivative of the entire interval


Find all values of “c” that satisfy the MVT.

1) [-7,1]




2) y=x⁻¹ [1,4]





Using related formulas to find the maximum or minimum solution to a problem


  • Sketch the problem
  • Write equations (target and constraints)
  • Combine equations
  • Determine domain
  • Find 1st derivative and critical points
  • Find maximum/minimum
  • Give answer in a sentence
example one
Example One

Two pens are to be constructed using a total of 900 feet of fencing. One pen is to be a square X by X and the other is to be a rectangle with one side twice as long as the other (X by 2X). Determine the dimensions of the pens so that the enclosed areas are as large as possible.



So the dimensions with the maximum area are 105.9 ft by 105.9 ft and 79.4 ft by 158.8 ft.



example two
Example Two

Given the curve y=x² in the first quadrant and a vertical line x=3, determine the inscribed rectangle of maximum area which has a right side on line x=3.

The rectangle is 2 by 4, so the area of the rectangle is 8.



related rates
Related Rates
  • Finding the rate at which a quantity changes by comparing to a known rate of change
  • Usually used in relation to time


1) Draw a picture

2) State wanted and known rates

3) Write formula to compare rates

4) Take the derivative

5) Plug in the known rate

6) Solve for unknown rate

example one1
Example One

A 20 foot ladder is leaning against a building. The ladder is sliding down the wall at a constant rate of 2 ft/sec. At what rate is the angle between the ladder and the ground changing when the top of the ladder is 12 feet from the ground?

The angle is changing at a rate of -1/8 radians per second.





example two1
Example Two

Water is flowing into and inverted cone at the rate of 5 in³/sec. If the cone has an altitude of 4 inches and a base radius of 3 inches, how fast is the water level rising when the water is 2 inches deep?


The water level is rising at 20/(9π) inches per second.



particle motion
Particle Motion
  • Particle motion is described by a function and its derivatives.
  • When given a function that describes a particles linear motion, the first derivative describes the particle's velocity and the absolute value of the first derivative gives speed.
  • The second derivative gives the particles acceleration.
example one2
Example One

Given the following equation that gives the position of a particle, find A) the velocity equation, B) the velocity at time 15 minutes, and C) the speed at 15 minutes.


B)f’(15)=-8.5 m/s

C)8.5 m/s

example two2
Example Two
  • The velocity (in centimeters per second) of a blood molecule flowing through a capillary of radius 0.008 cm is given by the equation below. Find the acceleration when r = 0.004

The acceleration at r=0.004 is -0.00008 centimeters per second squared.

linear approximation
Linear Approximation
  • Linear approximation is using the slope of a tangent line to approximate a value that is close to the point of tangency.
  • Δ f(x)=f’(a)-x (yes, the delta is upside down). Δf(x) = f(a + Δx) – f(a).
example one3
Example One
  • The cube root of 27 is 3. How much larger is the cube root of 27.2?
  • The derivative of f(x) is
  • Δf '(x)= (1/27)(0.2)
  • Δf '(x)= 1/135
  • So the cube root of 27.2 is 1/135 more than the cube root of 27
  • Estimated value =3.00740
  • Actual value=3.00739
example two3
Example Two
  • The price of a bus pass between Albuquerque and Los Alamos is set at x dollars, a bus company takes in a monthly revenue of in thousands of dollars. Estimate the change in revenue from $50 to $53.
  • ∆R'(50)=.5
  • .5*∆x = .5*3
  • = 1.5
  • So by increasing the tickets by three dollars the company's revenue goes up by $1500 to 51500. The actual value for $53 is $514100.