Atomic Mass Calculation and Isotope Abundance Equations
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Understand isotopic calculations, atomic masses, and periodic table concepts. Learn to calculate isotope masses, abundance percentages, and average atomic masses. Practice solving problems using isotopic data and formulas.
Atomic Mass Calculation and Isotope Abundance Equations
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First SAT given (1926) • Reading: Chapter 5 sections 1-5 (quiz) • Electron Configuration HW Due Tomorrow • HW 11: DUE Tomorrow • Chap. 11#’s 36, 45, 47, 49-52 (all), 59, 60, 63, 64, 65, 67, 99 (no extra credit) • HW #5.1: DUE Wednesday • 3, 4, 5, 8, 9, 11, 13, 25-35 (odd), 41, 45, 49, 57, 80, 81, 85, 89 • HW #5.2: DUE Thursday • 17, 19, 21, 39, 43, 47, 53, 59, 71-77 (all), 83 • For lab tomorrow (dry lab)
Atomic Masses • Measured in the unit amu • Stands for atomic mass unit • Defined as 1/12th the mass of a 12C atom • 35Cl = 34.9689 amu • 50V = 49.9472 amu • 79Br = 78.9183 amu • Are these what the P.T. say?
All Isotopes are NOT Created Equal • Weighted averages • An equation (oh crap) • 35Cl = 34.9689 amu • Abundance = 75.77% • 37Cl = 36.9659 amu • Abundance = 24.23% • These must be the only 2 isotopes... Why?
All Isotopes are NOT Created Equal • 35Cl = 34.9689 amu • Abundance = 75.77% • 37Cl = 36.9659 amu • Abundance = 24.23% =0.7577 =0.2423
All Isotopes are NOT Created Equal • 35Cl = 34.9689 amu • Abundance = 75.77% • 37Cl = 36.9659 amu • Abundance = 24.23% =0.7577 Where have I seen this before? =0.2423 x 0.2423 = 35.45amu x 0.7577 34.9689 + 36.9659 Periodic Table gives AVERAGE ATOMIC MASS in amu!!
Some Algebra and a New Equation decimal, not % (i.e. 0.1234 not 12.34%) For solving for % abundance multiply by 100 to get percentages
Isotopes Calculation Summary • DO NOT use “normal” averages • If asked for two percent-abundances, use: • If asked for ANYTHING else:
A Problem! What is the average atomic mass of magnesium? 78.90% of all magnesium is 24Mg 23.985 amu 10.00% of all magnesium is 25Mg 24.986 amu 11.10% of all magnesium is 26Mg 25.983 amu 11.10% 100.00% = 24.30 amu
Another Problem! Lead has 4 isotopes, the masses and abundances of which can be found in the following table. Your job? Calculate the isotope mass of lead-207. 22.10% ???? X = Lead-207 = 206.9 amu
A Problem! Bromine has 2 isotopes, and . has a mass of 78.9193 amu and has a mass of 80.9163 amu. What are the percent abundances of each of the isotopes? Abundance 1 = 50.44% Abundance 2 = 49.56%
A Problem! Thallium has 2 isotopes, and . has a mass of 202.973 amu and has a mass of 204.974 amu. What are the percent abundances of each of the isotopes? Abundance 1 = 30.2% Abundance 2 = 69.8%
The Modern Periodic Table • Mendeleev • Set up the periodic table based on atomic mass • Moseley • Set it up by atomic number rather than atomic mass • Periodic Law – properties occur in a repeating pattern when set up by atomic number.
The Modern Periodic Table • Periods (series) • Labeled 1 - 7
The Modern Periodic Table • Groups (families) • Columns • 2 different labeling systems • 1-18 • A-B
A few definitions… • Main Group Elements: • Groups 1 and 2 and 13 – 18 • Groups A
A few definitions… • Main Group Elements: • Groups 1 and 2 and 13 – 18 • Groups A • Transition Elements: • Groups 3 – 12 • Groups B
Groups of Elements • Vertical columns are called groups • Group 1 = Alkali Metals
Groups of Elements • Vertical columns are called groups • Group 1 = Alkali Metals • Group 2 = Alkaline Earth Metals
Groups of Elements • Vertical columns are called groups • Group 1 = Alkali Metals • Group 2 = Alkaline Earth Metals • Group 17 = Halogens
Groups of Elements • Vertical columns are called groups • Group 1 = Alkali Metals • Group 2 = Alkaline Earth Metals • Group 17 = Halogens • Group 18 = Noble Gases
The Modern Periodic Table • Representative elements • Also known as main group elements • Transition metals • Inner transition metals • Lanthanide series
The Modern Periodic Table • Representative elements • Also known as main group elements • Transition metals • Inner transition metals • Lanthanide series • Actinide series
Diatomic Elements • Elements that exist as diatomic molecules when UNCOMBINED (meaning not in a compound with other elements). H2, N2, O2, F2, Cl2, Br2, I2
Diatomic Elements • Elements the exist as diatomic molecules when UNCOMBINED (meaning not in a compound with other elements). H2, N2, O2, F2, Cl2, Br2, I2 NaCl BiF5 K3N Examples of when these elements are NOT diatomic AlI3 TiBr4
Atoms vs. Ions • Atoms are NEUTRAL!!!!! • This means that they have zero charge • #p+ = #e-
Charge!!! e- = -1 p+ = 1 + 0 47 e- = -47 47 p+ = 47 + 0 When #p+ = #e-, the atom has no charge and is neutral
Atoms vs. Ions • Atoms can gain or lose e- to form IONS • ANY charged particle is called an ion • Losing e- gives POSITIVELY charge
Charge!!! When an atom LOSES electrons 11 p+ = 11 -10 10 e- = 11 e- = +1
Atoms vs. Ions • Atoms can gain or lose e- to form IONS • ANY charged particle is called an ion • Losing e- gives POSITIVELY charge • Called cations • Usually formed from metals • Gaining e- gives a NEGATIVELY charged ion
Atoms vs. Ions • Atoms can gain or lose e- to form IONS • ANY charged particle is called an ion • Losing e- gives POSITIVELY charge • Called cations • Usually formed from metals • Gaining e- gives a NEGATIVELY charged ion • Called anions • Usually formed from non-metals
Charge!!! When an atom LOSES electrons 11 p+ = 11 10 e- = -10 +1 16 p+ = 16 When an atom GAINS electrons -18 16 e- = 18 e- = -2
Atoms vs. Ions • Atoms can gain or lose e- to form IONS • ANY charged particle is called an ion • Losing e- gives POSITIVELY charge • Called cations • Usually formed from metals • Gaining e- gives a NEGATIVELY charged ion • Called anions • Usually formed from non-metals
How many electrons are needed to be neutral? 15 protons
15 protons 2 electrons
15 protons 10 electrons
Total charge = 0 Stable!!! 15 protons 15 electrons
Total charge = p+ - e- = 15 – 18 = -3 Stable!! 15 protons 18 electrons
How many electrons are needed to be neutral? 12 protons
12 protons 2 electrons